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3 years ago

What is the equation of a line with a slope of 7 and a point (1, 8) on the line?

1 answer:

8 0

Y = mx + b
slope(m) = 7
(1,8)...x = 1 and y = 8
now we sub into the formula and find b, the y int
8 = 7(1) + b
8 = 7 + b
8 - 7 = b
1 = b
so ur equation is : y = 7x + 1 <===

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$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

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$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

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