Hey there mate ;)
The answer for proving your question is sent as image. Please check.
Thank you !
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>e</em><em>d</em><em> </em><em>b</em><em>y</em><em> </em><em>B</em><em>e</em><em>n</em><em>j</em><em>e</em><em>m</em><em>i</em><em>n</em>
Answer:
The equation is R = 20d + m(1)
Where R is the rental amount in dollars, d is the number of days and m is the number of miles driven
R for 3 days and 1000 miles is $1,060
Step-by-step explanation:
To properly represent the algebraic expression, we need to assign some variables.
Now, let the rental amount be R, the number of miles driven be m and the number of days rented for is d
Thus, we can say that:
R = 20d+ m(1)
Where R is rental amount, m is the number of miles driven and d is the number of days for which the truck was driven.
Now we are asked to calculate rental amount for 3 days and 1000 miles.
R = 20d + m(1)
R = 20(3) + 1000(1)
R = 60 + 1000
R = $1,060
Answer:
D
Step-by-step explanation:
