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enot [183]
4 years ago
13

Algebraic equation of 185 is less than a number

Mathematics
1 answer:
kkurt [141]4 years ago
4 0

Answer:

n-185

Step-by-step explanation:

since 185 needs to be subtracted from a number, or n

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For his phone service, Ivan pays a monthly fee of $14, and he pays an additional $0.05 per minute of use. The least he has been
Tomtit [17]

Answer:

1215 minutes are the possible numbers he has used his phone in a month.

Step-by-step explanation:

He has a monthly fee of 14$ then to the least that he has been charged we need to substract the monthly fee as follows:

Monthly charged = 74,75-14

Monthly charged= 60,75$

Then he pays an additional 0,05 $/minute of use, to know the consume:

Minutes= \frac{60,75}{0,05}

Minutes= 1215 possible numbers of minutes he has used his phone.

8 0
3 years ago
"Express as a mixed numeral: 39/8" is a problem found in a fifth-grade arithmetic textbook. This problem is BEST solved through:
Scilla [17]

Answer:

  c.  an algorithm

Step-by-step explanation:

Most math problems are best solved using an algorithm. Certainly, converting numbers from one form to another is easily done that way.

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The integer part is the whole-number quotient of the division. The fractional part is the remainder divided by the denominator:

  39/8 = 32/8 + 7/8 = 4 7/8

5 0
3 years ago
Mike scored a 125 at a semi-final dividing competition season. He scored 95 at this final season. What is the percentage decreas
IrinaK [193]

Answer:

There was a 24% decrease

Step-by-step explanation:

Percentage decrease = (final season's score - semi-final score) / semi final score x 100

\frac{95-125}{125} ×100

\frac{-30}{125} × 100 = -24%

3 0
3 years ago
Which are the correct steps for solving the equation ? Select all that apply
Radda [10]
I would love to help, but what are the options?
8 0
3 years ago
A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those date
Anni [7]

Answer:

Confidence interval variance [21.297 ; 64.493]

Confidence interval standard deviation;

4.615, 8.031

Step-by-step explanation:

Given :

Variance, s² = 34.34

Standard deviation, s = 5.86

Sample size, n = 27

Degree of freedom, df = 27 - 1 = 26

Using the relation for the confidence interval :

[s²(n - 1) / X²α/2, n-1] ; [s²(n - 1) / X²1-α/2, n-1]

From the chi distribition table :

X²α/2, n-1 = 41.923 ; X²1-α/2, n-1 = 13.844

Hence,

[34.34*26 / 41.923] ; [34.34*26 / 13.844]

[21.297 ; 64.493]

The 95% confidence interval for the population variance is :

21.297 < σ² < 64.493

Standard deviation is the square root of variance, hence,

The 95% confidence interval for the population standard deviation is :

4.615 < σ < 8.031

3 0
3 years ago
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