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enot [183]
4 years ago
13

Algebraic equation of 185 is less than a number

Mathematics
1 answer:
kkurt [141]4 years ago
4 0

Answer:

n-185

Step-by-step explanation:

since 185 needs to be subtracted from a number, or n

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Sergio [31]

Answer:No

Step-by-step explanation:

4 0
3 years ago
2,5, 25/2, ... <br> find the 10th term
notka56 [123]

Answer:

The  10^{th} term of the given sequence

t_{10} = \frac{5^{9} }{2^{8} }

Step-by-step explanation:

<u>Step(i):-</u>

Given sequence   2 , 5, \frac{25}{2}

First term    a = 2

The difference of given geometric sequence

    d = \frac{r_{2} }{r_{1} } = \frac{5}{2}

<u><em>Step(ii):-</em></u>

The  n^{th} term of the given sequence

t_{n} = ar^{n-1}

The  10^{th} term of the given sequence

t_{10} = (2)(\frac{5}{2} )^{10-1}

t_{10} = (2)(\frac{5}{2} )^{9}= \frac{5^{9} }{2^{8} }

8 0
3 years ago
I’m so confused. can someone please help
lilavasa [31]

Answer:

k = - 6

Step-by-step explanation:

Given a function f(x), then a horizontal translation parallel to the x- axis is denoted by

f(x + k)

If k > 0 then shift of k units left

If k < 0 then shift of k units right

Here the shift is 6 units to the left, from 4 to - 2, hence

k =  6

3 0
4 years ago
Use an algebraic approach to solve the problem.
qaws [65]

Answer:

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

Step-by-step explanation:

Use the formula for the mean: sum of elements / number of elements

Let x represent her first exam score.

Her second exam score can be represented by x + 11, since it was 11 points better than her first.

Her third exam score can be represented by (x + 11) + 5, since it was 5 points better than her second.

Plug in all of these expressions into the mean formula. Plug in 87 as the mean, and plug in 3 as the number of elements (since there are 3 scores):

mean = sum of elements / number of elements

87 =  ( (x) + (x + 11) + (x + 11) + 5 ) / 3

Add like terms and solve for x:

87 = (3x + 27) / 3

261 = 3x + 27

234 = 3x

78 = x

So, her first score was a 78.

Find her second score by adding 11 to this:

78 + 11 = 89

Find her third score by adding 5 to the second score:

89 + 5 = 94

Her first exam score was a 78, her second exam score was a 89, and his third exam score was a 94.

6 0
3 years ago
30 points for anyone that can solve the question ​
marusya05 [52]

The solution to this problem is 5/2a^2b^5

5 0
3 years ago
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