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GaryK [48]
3 years ago
15

Find the slope of the line through (2,-2) and 5,-1)

Mathematics
1 answer:
Kitty [74]3 years ago
4 0

Answer:

m=\frac{1}{3}

Step-by-step explanation:

\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}\\\\\left(x_1,\:y_1\right)=\left(2,\:-2\right),\:\\\left(x_2,\:y_2\right)=\left(5,\:-1\right)\\\\m=\frac{-1-\left(-2\right)}{5-2}\\\\m = \frac{-1+2}{3}\\ \\Simplify\\m = \frac{1}{3}

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(1,3)
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(3-(-2))/(1-3)=(3+2)/(1-3)=5/-2

slope is -5/2
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Step-by-step explanation:

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What is 4/7 divided by 2/7
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To divide one fraction by another, invert (turn upside-down) the second fraction, then multiply.
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3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
2 years ago
-12-x&gt;-12+4x<br> put the steps too pls thanks
andrey2020 [161]

Answer:

x < 0

Step-by-step explanation:

Firstly put the values with variable x to one side,

; -12 - x > -12 + 4x

; -12 + 12 > 4x + x

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then divide both sides by 5,

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; Hence the solution to the inequality above,

; x < 0...always remember to reverse the sign when you change the side to which you put the variable of x,

Therefore...( x < 0 )

3 0
3 years ago
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