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4 years ago

PLEASE HELP AGAIN WILL MARK BRAINLEST !!!!!

Mathematics

1 answer:

Archy [21]4 years ago

7 0

Answer:

Step-by-step explanation:

g(-1) means what is g(x) when x=-1.

So find -1 under the column labeled x and then scroll directly to the right of that and you should see what g(-1). It is 3

Here are my examples:

g(-8)=6

g(-5)=-2

g(-1)=3

g(0)=-5

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SSSSS [86.1K]

(B)
if <em>f</em>(a) = K, then that means <em>f </em>sends (a) to (K).
the inverse function, <em>f</em>-1, goes back where you started, so <em>f</em>-1 <em />sends (K) to (a).
<em>f</em>-1(K) = a.

8 0

3 years ago

Read 2 more answers

Simplify the sum.<br> (4u3 + 4u2 + 2) + (6u3 – 2u + 8)

Elan Coil [88]

Answer:

$10u^{3}+4u^{2}-2u+10$ or $2(5u^{3}+2u^{2}-u+5)$

Step-by-step explanation:

we have

$(4u^{3}+4u^{2} +2)+(6u^{3}-2u+8)$

step 1

Group terms that contain the same variable

$(4u^{3}+6u^{3})+(4u^{2})+(-2u)+(2+8)$

step 2

Combine like terms

$(10u^{3})+(4u^{2})+(-2u)+(10)$

step 3

Eliminate parenthesis

$10u^{3}+4u^{2}-2u+10$

step 4

Factor the number $2$

$2(5u^{3}+2u^{2}-u+5)$

8 0

3 years ago

Read 2 more answers

B is the midpoint of AC. What is the length of AB? AB is 9x+7 and BC is -3x+20

ahrayia [7]

<h3>Answer:</h3>

$AB = \frac{67}{4}\\$

<h3>Step-by-step explanation:</h3>

If $B$ is the midpoint of $\overline{AC}$ then $AB$ is just half of $AC$ and also, $BC$ is just half of $AC$ . This means that $AB$ must be equal to $BC$ . Essentially, $9x +7 = -3x +20$ and we can solve for the of $x$ from that equation.

$9x +7 = -3x +20 \\ 9x +7 +3x = -3x +20 +3x \\ 12x +7 = 20 \\ 12x +7 -7 = 20 -7 \\ 12x = 13 \\ \frac{12x}{12} = \frac{13}{12} \\ x = \frac{13}{12}$

Now we can solve for $AB$

$AB = 9(\frac{13}{12}) +7 \\ AB = 3(\frac{13}{4}) +7 \\ AB = \frac{39}{4} +7 \\ AB = \frac{39}{4} +\frac{28}{4} \\ AB = \frac{67}{4}$

8 0

3 years ago

Use rules of transformations to answer each of the items below. Be sure to answer in complete sentences, and when necessary, inc

cestrela7 [59]

We choose the coordinates (4,4), (4,10), and (8,4) as the vertices of right-angle triangle ABC

We want to dilate triangle ABC by scale factor of 2 at the center (0,2)

The image is shown below as triangle A'B'C' with coordinates (8.6), (8,18), and (18,6).

Triangle ABC has a base of 4 units and a height of 6 units
Triangle A'B'C' has a base of 8 units and a height of 12 units

Applying Pythagoras theorem to triangle ABC to find the hypotenuse
$BC^{2}= AB^{2}+ AC^{2}$
$BC^{2}= 4^{2}+ 6^{2}$
$BC^{2} =52$
$BC=2 \sqrt{13}$

Now, we calculate the hypotenuse of the image
$B'C'^{2}= A'B'^{2}+ A'C'^{2}$
$B'C'^{2}= 8^{2}+ 12^{2}$
$B'C'^{2}=208$
$B'C'= \sqrt{208} =4 \sqrt{13}$

The hypotenuse of the image is twice the hypotenuse of triangle ABC which proof the two shapes are similar shape

7 0

3 years ago

(Multiple choice/ Most Brainly will be rewarded)

GaryK [48]

Answer:

Step-by-step explanation

you have to do (2^3)(a^4*3)(b^2*3) which gets you 8a^12b^6

then you have (8a^12b^6)*(3ab^4) so you do (8*3)(a^12+1)(b^6+4)

which equals 24a^13b^10

and therefore the answer is 3

4 0

3 years ago