Answer:
We can predict that the spinner will possible land on the green or blue 8 out of 12 times, or 66% of the time.
Step-by-step explanation:
First of all, we need to calculate the percentage of the spinner that is both green and blue.
There are a total of 12 sections on the spinner.
6 out of 12 of the sections are green. 6/12 = 0.5 or a 50% change
2 out of 12 of the secions are blue. 2/12 = 0.16 or a 16% change
3 out of 12 of the sections are pink. 3/12 = 0.25 or a 25% chance
1 out of 12 sections are yellow. 1/12 = 0.08 or a 8% chance
Athough I provided the percantages for each color, all we really need is the data for the green and blue.
0.5 + 0.16 = 0.66
12 x 0.66 = 7.92 or 8 when rounded to the nearest whole number
Therefore, we can predict that the spinner will possible land on the green or blue 8 out of 12 times, or 66% of the time.
Hope this helps! Have a blessed day! :)
If The domain is all real numbers then the range is All real numbers equal or greater than -5
0.9544 = 95.44% of scores lie between 220 and 380 points.
Normal distribution problems can be solved using the Z-score formula.
With a set of means and standard deviations, the Z-score for measure X is given by: After finding the Z-score, look at the Z-score table to find the p-value associated with that Z-score. This p-value is the probability that the value of the measure is less than X. H. Percentile of X. Subtract 1 from the p-value to get the probability that the value of the measure is greater than X.

We are given mean 300, standard deviation 40.
This means that µ= 300, σ = 40
What proportion of scores lie between 220 and 380 points?
This is the p-value of Z when X = 380 subtracted by the p-value of Z when X = 220.
X = 380

Z= (380-300)/40
Z= 2
Z=2 has a p-value of 0.9772.
X=300

Z= (220-380)/40
Z=-2
Z=-2 has a p-value of 0.9772.
0,9772 - 0,0228 = 0,9544
0.9544 = 95.44% of scores lie between 220 and 380 points.
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