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3 years ago

PLEASE HELP I HAVE PICTURE!!!

Mathematics

1 answer:

ludmilkaskok [199]3 years ago

4 0

3rd option: $-\frac{1}{2} < t \leq 3$ is the correct answer

Step-by-step explanation:

First of all, we have to observe the number line

Observing the number line we can see that the number -0.5 or -1/2 is not included in the solution as the circle on -1/2 is empty. An empty circle means that the number is not included in the solution.

While on the other side we can see that 3 has a filled circle which means 3 is included in the solution

This means that the solution might be:

$t>-0.5\\and\\t \leq 3$

By comparing the observation and the answer choices we can conclude that

3rd option: $-\frac{1}{2} < t \leq 3$ is the correct answer

Keywords: Inequalities, solution

Learn more about inequalities at:

#LearnwithBrainly

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.4^3Grafting, the uniting of the stem of one plant with the stem or root of another, is widely used commercially to grow the ste

11111nata11111 [884]

Answer:

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

Step-by-step explanation:

To solve this question, we need to understand the binomial probability distribution and conditional probability.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: No failed grafts in the first seven

Event B: At least one fail in the next three.

Intersection of events A and B:

Since the probability of a graft failling is independent of other grafts, we have that:

$P(A \cap B) = P(A)*P(B)$

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{P(A)*P(B)}{P(A)} = P(B)$

So we just have to find the probability of one fail in three trials.

Three trials means that $n = 3$ .

The probability is

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.4)^{0}.(0.6)^{3} = 0.216$

Then

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.216 = 0.784$

0.784 = 78.4% probability that there will be at least one failed graft in the next three done

3 0

3 years ago

What’s the correct answer for this?

jek_recluse [69]

Answer:

I believe that the answer is 24.

6 0

3 years ago

The table below shows the relationship between the number of parents in a household and the number of children in the same house

jolli1 [7]

Answer: ???

Step-by-step explanation: There is no table shown.

7 0

3 years ago

Find

Zarrin [17]

The measures of two complementary angles are 64 degrees and 26 degrees

<h3><u>Solution:</u></h3>

Let the larger angle be "a" and smaller angle be "b"

<em>Two angles are Complementary when they add up to 90 degrees</em>

so we get,

a + b = 90 ------ eqn 1

Given that measure of the larger angle is 12 more than twice the measure of the smaller angle

larger angle = 12 + 2(smaller angle)

a = 12 + 2b --- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to get values of "a" and "b"</u></em>

Substitute eqn 2 in eqn 1

12 + 2b + b = 90

12 + 3b = 90

3b = 90 - 12

3b = 78

Therefore from eqn 2,

a = 12 + 2b

a = 12 + 2(26)

a = 12 + 52

Thus the measures of two complementary angles are 64 degrees and 26 degrees

7 0

3 years ago

Select the graph that represents the inequality below NO LINKS

Nonamiya [84]

Answer:

First option is correct answer that is arrow turning in right side.

You can follow me to get more answer.

8 0

3 years ago