Answer:
Step-by-step explanation:
I think it would be 9, but the graph seems a bit unclear so I’m really sorry if that doesn’t help..
Well I don't know.
Let's think about it:
-- There are 6 possibilities for each role.
So 36 possibilities for 2 rolls.
Doesn't take us anywhere.
New direction:
-- If the first roll is odd, then you need another odd on the second one.
-- If the first roll is even, then you need another even on the second one.
This may be the key, right here !
-- The die has 3 odds and 3 evens.
-- Probability of an odd followed by another odd = (1/2) x (1/2) = 1/4
-- Probability of an even followed by another even = (1/2) x (1/2) = 1/4
I'm sure this is it. I'm a little shaky on how to combine those 2 probs.
Ah hah !
Try this:
Probability of either 1 sequence or the other one is (1/4) + (1/4) = 1/2 .
That means ... Regardless of what the first roll is, the probability of
the second roll matching it in oddness or evenness is 1/2 .
So the probability of 2 rolls that sum to an even number is 1/2 = 50% .
Is this reasonable, or sleazy ?
Answer: G
Explanation/Calculation:
You can clearly see that the white shapes are positive while the black shapes are negative. You can determine this because all (except F) claim that the 6 shapes are negative.
To make it easier, use elimination. It's definitely not J because you are not subtracting -6, but adding (as seen in the equation.) It is not F because 2(3)=6 when the equation needs -6.
So it is either G or H...
H claims that 12x+3+(-6) is what the model symbolizes; but this is incorrect. Unless x is a decimal, you can not have the large shape as the "purest" form (so to speak.) The "purest" state you can go in this model is a cube/square which=1.
Therefore, "G Jamey modeled 12 + 3x + (-6) and it is equivalent to 12x-3" is the correct answer.
Hope this helps you!
