Find the inequality represented by the graph<br> (0,2) (2,3)

Can a right triangle be formed using these squares

Alona [7]

The answer is yes. all 3 of those triangles have perfect square roots, being 5, 12, and 13 respectively. I hope this helps! Could I possibly get brainliest?

4 0

3 years ago

Read 2 more answers

7.19 divided by 58 estimate the quotients

lozanna [386]

Answer:

0.124

Step-by-step explanation:

$\frac{7.19}{58}$

To divide the numbers, we need to remove the decimal point

To remove decimal point , we multiply top and bottom by 100

$\frac{719}{5800}$

Use long division. After using decimal point at the top we can include any number of zeros with 719

. 1 2 3 9

---------------------

5800 7190

5800

------------------------(subtract)

13900

11600

---------------------------(subtract)

2300 0

1740 0

--------------------------(subtract)

56000

52200

---------------------------(subtract)

3800 0

Division goes on ............

Estimate the quotient to 3 decimal places

Quotient = 0.124

6 0

2 years ago

Lila deposits her earnings from teaching children in a bank account. She has the peace of mind that her money will remain safe i

liberstina [14]

Answer: Lila is incorrect about transferring money through checks.

Step-by-step explanation: If Lila transfers money through checks then she is adding money to her bank account funds and increasing her interests if she leaves the money there for a while.

6 0

3 years ago

Assume that the helium porosity of coal samples taken from any particular seam is Normally distributed with true standard deviat

riadik2000 [5.3K]

Answer:

a) $4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

b) $4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

c) $n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

Step-by-step explanation:

Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.33$

Now we have everything in order to replace into formula (1):

$4.85-2.33\frac{0.75}{\sqrt{20}}=4.46$

$4.85+2.33\frac{0.75}{\sqrt{20}}=5.24$

Part b

$4.56-2.33\frac{0.75}{\sqrt{16}}=4.12$

$4.56+2.33\frac{0.75}{\sqrt{16}}=4.99$

Part c

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =0.4/2 =0.2 we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(0.75)}{0.2})^2 =54.02 \approx 55$

5 0

3 years ago

2) There are 152 students and 8 teachers in 7th grade at Wilson STEM Academy. a) What is the ratio of students per teacher? b) H

tatyana61 [14]

Answer:

Students per teacher 152:8

128 students

Step-by-step explanation:

4 0

2 years ago

Find the inequality represented by the graph (0,2) (2,3)