Answer: 0.39
Step-by-step explanation:
Given the following classification :
Heavy smokers (H) = 10%
Light smokers (L) = 20%
Non smokers (N) = 70%
Given that :
The death rates of the heavy and light smokers were five and three times that of the nonsmokers, respectively
Let probability of death = D
P(D | N) = d
P(D | H) = 5d
P(D | L) = 3d
Hence,
P(D) = [P(H) * P(D | H) + P(L) * P(D | L) + P(N) * P(D | N)]
P(D) = [0.1 * 5d + 0.2 * 3d + 0.7 * d]
P(D) = [0.5d + 0.6d + 0.7d]
P(D) = 1.8d
A randomly selected participant died over the five-year period: calculate the probability that the participant was a nonsmoker.
P(N | D) = [P(N) * P(D | N)] / P(D)
P(N | D) = 0.7d / 1.8d
P(N | D) = 0.3888
= 0.39
Answer:
???
Step-by-step explanation:
Do you not have the full equation posted because t=1 is t=1
Answer:
Yes
Step-by-step explanation:
44÷4=11
318÷4=79.5
912÷4=228
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Hello!</h2>
The answer is: 4.0 (at Richter scale)
<h2>Why?</h2>
The answer is 4.0 Assuming the standard earthquake as 1.0 (at Richter scale).
An earthquake of 1.0 at Richter scale is equal to:
An earquake of 2.0 at Richter scale is equal to:
and so...
Therefore,
An earthquake of 4.0 at the Richter scale is equal to:
So, it means that an earthquake with 4.0 magnitude at the Richter scale is 10000 times more intense than a standard earthquake, assuming it as 1.0 at Richter scale magnitude.
Have a nice day!
Answer:
You always do the X-axis first. Hope this helps! :)
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CloutAnswers</h3>