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ale4655 [162]
3 years ago
5

How do you divide decimals?

Mathematics
1 answer:
MakcuM [25]3 years ago
3 0
You use long division to divide decimals
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Hey can you please help! posted picture of question
frosja888 [35]
The solution of the system can be x - 3y = 4 only if both the equations can be simplified to x - 3y = 4.

This will mean that both the equations will result in the same line which is x - 3y = 4 and thus have infinitely many solutions.

Second equation is:

Qx - 6y = 8 
Taking 2 common we get:

(Q/2)x - 3y = 4

Comparing this equation to x- 3y = 4, we can say that 

Q/2 = 1
So,
Q = 2

Therefore, the second equation will be:

2x - 6y = 8
5 0
3 years ago
Which expression is the best estimate of the product of 7/8and 8 1/10?
Vitek1552 [10]

Answer:

7 7/80 or 7.0875

Step-by-step explanation:

product is the result of multiplication

7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875

5 0
3 years ago
If x=4 then what is x+x-x
qaws [65]
4 Is the answer since 4 is x 4+4 is 8 8-4 is 4 :)
6 0
3 years ago
Read 2 more answers
does the following system of equations have a solution if so find it. 2x+y+z= 4 x-y+3z= -2 -x+y+z= -2
saul85 [17]
I'd suggest using "elimination by addition and subtraction" here, altho' there are other approaches (such as matrices, substitution, etc.).

Note that if you add the 3rd equation to the second, the x terms cancel out, and you are left with the system

 - y + 3z = -2
   y  + z  =  -2
-----------------
         4z = -4, so z = -1.

Next, multiply the 3rd equation by 2:  You'll get -2x + 2y + 2z = -2.

Add this result to the first equation.  The 2x terms will cancel, leaving you with the system

2y + 2z = -2
  y  +  z  = 4

This would be a good time to subst. -1 for z.  We then get:

-2y - 2 = -2.  Then y must be 0.  y = 0.

Now subst. -1 for z and 0 for y in any of the original equations.

For example, x - (-1) + 3(0) = -2, so x + 1 = -2, or x = -3.

Then a tentative solution is     (-3, -1, 0).

It's very important that you ensure that this satisfies all 3 of the originale quations.
5 0
3 years ago
obtain the equation of two points passing of lines 4x-3y-1=0 and 2x-3y+3=0 and equally inclined to the axes​
klasskru [66]

Answer:By 8(4)P.5, the slope of the line equally inclined to axes is tan(±45  

o

)=±1. Hence by P+λQ=0,

5λ+3

2λ+4

​

=±1

⇒λ=  

3

1

​

,−1. Putting for λ, the two lines are

x−y=0,x+y−2=0.

Was this answer helpful

8 0
3 years ago
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