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lana [24]
2 years ago
7

Find the length of the third side of the right triangle. Give an exact answer and an approximation to three decimal places if ne

eded.

Mathematics
1 answer:
trasher [3.6K]2 years ago
8 0

Answer:

a = 32

Step-by-step explanation:

This is a right triangle and the square value of hypotenuse is equal to sum of square value of other two side lengths

68^2 = 60^2 + a^2

4624 = 3600 + a^2

4624 - 3600 = a^2

1024 = a^2 find the root for both sides

32 = a

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My name is Ann [436]

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7 0
3 years ago
What is the measure for the following ∠?<br> m∠BOA<br><br> 20<br> 40<br> 60
kaheart [24]

Hello!

First, find angle BOA on the protractor. To do this, look for point B, point O, and point A.

Now, we see some markings that mark what degree point B and point A are at. Point B is marked at 60 degrees, and Point A 40 degrees.

Now, all that's left to do, is subtract the two measurements.

60 degrees - 40 degrees = 20 degrees

Therefore, your answer is 20.

Hope this helps!

8 0
3 years ago
This is my last question please help!!!
galina1969 [7]
I believe the answer is 6
5 0
3 years ago
Read 2 more answers
Foster makes sandwiches at a deli. There are 8 1/2 (eight and one half) pounds of turkey at the deli. How many 1/4 (one fourth)p
atroni [7]

foster can make 42 1/4-pound turkey sandwiches

explanation: 10.5 divided by 1/4 is 42

4 0
3 years ago
Answer ASAP. Please give correct answer. (Involves a bunch of circles and trig identities)
iren [92.7K]

Answer:

45.40

Step-by-step explanation:

First of all, the shape of rope is not a parabola but a catenary, and all catenaries are similar, defined by:

y=acoshxa

You just have to figure out where the origin is (see picture). The hight of the lowest point on the rope is 20 and the pole is 50 meters high. So the end point must be a+(50−20) above the x-axis. In other words (d/2,a+30) must be a point on the catenary:

a+30=acoshd2a(1)

The lenght of the catenary is given by the following formula (which can be proved easily):

s=asinhx2a−asinhx1a

where x1,x2 are x-cooridanates of ending points. In our case:

80=2asinhd2a

40=asinhd2a(2)

You have to solve the system of two equations, (1) and (2), with two unknowns (a,d). It's fairly straightforward.

Square (1) and (2) and subtract. You will get:

(a+30)2−402=a2

Calculate a from this equation, replace that value into (1) or (2) to evaluate d.

My calculation:

a=353≈11.67

d=703arccosh257≈45.40

7 0
3 years ago
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