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Papessa [141]
3 years ago
12

What grade should I take AP classes?

Mathematics
2 answers:
natali 33 [55]3 years ago
8 0
11th grade 100% you can take them in 9th right but it’s too much
Ronch [10]3 years ago
7 0
Well… you can take AP courses and exams as early as 9th grade, but I don't recommend it. I think certain AP subjects, such as European History and World History, are great choices for 10th graders. But most AP classes are best suited to high school juniors and seniors.

Hope I can help you!
You might be interested in
Consider a normal distribution curve where the middle 85 % of the area under the curve lies above the interval ( 8 , 14 ). Use t
NeTakaya

Answer:

\mu = 11

\sigma = 2.08

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Middle 85%.

Values of X when Z has a pvalue of 0.5 - 0.85/2 = 0.075 to 0.5 + 0.85/2 = 0.925

Above the interval (8,14)

This means that when Z has a pvalue of 0.075, X = 8. So when Z = -1.44, X = 8. So

Z = \frac{X - \mu}{\sigma}

-1.44 = \frac{8 - \mu}{\sigma}

8 - \mu = -1.44\sigma

\mu = 8 + 1.44\sigma

Also, when X = 14, Z has a pvalue of 0.925, so when X = 8, Z = 1.44

Z = \frac{X - \mu}{\sigma}

1.44 = \frac{14 - \mu}{\sigma}

14 - \mu = 1.44\sigma

1.44\sigma = 14 - \mu

Replacing in the first equation

\mu = 8 + 1.44\sigma

\mu = 8 + 14 - \mu

2\mu = 22

\mu = \frac{22}{2}

\mu = 11

Standard deviation:

1.44\sigma = 14 - \mu

1.44\sigma = 14 - 11

\sigma = \frac{3}{1.44}

\sigma = 2.08

7 0
3 years ago
What is 5,821 g = ___ dag
pogonyaev

Answer:

582.1

Step-by-step explanation:

3 0
1 year ago
Which order pair could represent the location of point h
Rus_ich [418]
What does the work look like first
5 0
3 years ago
PLEASE HELP ME!
Westkost [7]

Answer:

75.09%

Step-by-step explanation:

1st week: 1060

2nd week: 950

3rd week: 1090

4th week: 795

Percent decrease from first to fourth week is 75.09%

Hope this helps!

Plz Mark Brainliest!

5 0
3 years ago
Suppose that you are in charge of evaluating teacher performance at a large elementary school. One tool you have for this evalua
Strike441 [17]

Answer:

a) Standard error = 2

b) Range = (76.08, 83.92)

c) P=0.69

d) Smaller

e) Greater

Step-by-step explanation:

a) When we have a sample taken out of the population, the standard error of the mean is calculated as:

\sigma_m=\dfrac{\sigma}{\sqrt{n}}=\dfrac{10}{\sqrt{25}}=\dfrac{10}{5}=2

where n is te sample size (n=25) and σ is the population standard deviation (σ=10).

Then, the standard error of the classroom average score is 2.

b) The calculations for this range are the same that for the confidence interval, with the difference that we know the population mean.

The population standard deviation is know and is σ=10.

The population mean is M=80.

The sample size is N=25.

The standard error of the mean is σM=2.

The z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_M=1.96 \cdot 2=3.92

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 80-3.92=76.08\\\\UL=M+t \cdot s_M = 80+3.92=83.92

The range that we expect the average classroom test score to fall 95% of the time is (76.08, 83.92).

c) We can calculate this by calculating the z-score of X=79.

z=\dfrac{X-\mu}{\sigma}=\dfrac{79-80}{2}=\dfrac{-1}{2}=-0.5

Then, the probability of getting a average score of 79 or higher is:

P(X>79)=P(z>-0.5)=0.69146

The approximate probability that a classroom will have an average test score of 79 or higher is 0.69.

d) If the sample is smaller, the standard error is bigger (as the square root of the sample size is in the denominator), so the spread of the probability distribution is more. This results then in a smaller probability for any range.

e) If the population standard deviation is smaller, the standard error for the sample (the classroom) become smaller too. This means that the values are more concentrated around the mean (less spread). This results in a higher probability for every range that include the mean.

6 0
3 years ago
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