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Yuki888 [10]
3 years ago
8

Simplify (4^7/5^2)^3

Mathematics
2 answers:
zloy xaker [14]3 years ago
8 0

Answer:

281,474,976.7

Step-by-step explanation:

we have from statement:

(4^7/5^2)^3

we can write:

4^7=4*4*4*4*4*4*4

5^2=5*5

so we have:

(4*4*4*4*4*4*4/5*5)^3=(16,384/25)^3

(16,384/25)^3= (655.36)^3

(655.36)^3= 655.36*655.36*655.36=281,474,976.7

dolphi86 [110]3 years ago
4 0
You first multiply 7 by itself 4 times which is 2401. Then you divide by 25 because 5 to the power of 2 is 25. Then you multiply by itself 3 times which gives you 885,842.381
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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
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\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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Step-by-step explanation:

Given

See attachment for class

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Where

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Upper \to Upper class interval

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Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

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\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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