Simplify (4^7/5^2)^3

Mathematics

2 answers:

zloy xaker [14]3 years ago

8 0

Answer:

281,474,976.7

Step-by-step explanation:

we have from statement:

(4^7/5^2)^3

we can write:

4^7=4*4*4*4*4*4*4

5^2=5*5

so we have:

(4*4*4*4*4*4*4/5*5)^3=(16,384/25)^3

(16,384/25)^3= (655.36)^3

(655.36)^3= 655.36*655.36*655.36=281,474,976.7

dolphi86 [110]3 years ago

4 0

You first multiply 7 by itself 4 times which is 2401. Then you divide by 25 because 5 to the power of 2 is 25. Then you multiply by itself 3 times which gives you 885,842.381

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A go-cart racetrack has 100-meter straightaways and semicircular ends with diameters of 40 meters. Calculate the average speed i

emmainna [20.7K]

Answer:

Average speed of go cart is 217.07 meters per minute.

Step-by-step explanation:

We are given the following in the question:

Length of straightway racetrack = 100 m

Diameter of semicircular end = 40 m

Radius =

$r = \dfrac{d}{2} = \dfrac{40}{2} = 20\text{ m}$

Perimeter of racetrack =

Perimeter of semicircle + 2(Length of straightway) + Perimeter of semicircle

$=\pi r + 2(100) + \pi r\\=2\pi r + 2(200)\\=(2\times 3.14\times 20) + 200\\=325.6\text{ m}$

Speed =

$s = \dfrac{\text{Distance}}{\text{Time}}\\\\s = \dfrac{4\times \text{Perimeter of track}}{6}\\\\s = \dfrac{4\times 325.6}{6}\\\\s = 217.06\text{ meter per minute}$