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2 years ago

7

Lilith is making a snack mix for her friends. The recipe shows the amount of each ingredient needed to make 8 bags. If Lilith fo

llows the recipe, which statement is true?

1 answer:

Reika [66]2 years ago

6 0

Please show me the options and possibly a screenshot of the question\

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What is the relation between the variables in the equation x^4/y=7?

makkiz [27]

Answer:

So, the relation between variables are

$y=\frac{x^4}{7}$

Step-by-step explanation:

We are given

$\frac{x^4}{y}=7$

Since, we have to find relation between variables

so, we can solve for y

$\frac{x^4}{y}=7$

Firstly, we will multiply both sides by y

$\frac{x^4}{y}\times y=7\times y$

we can simplify it

$x^4=7\times y$

we can isolate y

so, we can divide both sides by 7

so, we get

$y=\frac{x^4}{7}$

8 0

2 years ago

Is this correct ? My answers 10 btw. NO BEGINNERS , & whoever answers first gets a thanks :)

borishaifa [10]

The answer would be 54

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3 years ago

Solve for -6+3x=x-2+4x

Iteru [2.4K]

Answer:

x= -2

Step-by-step explanation: If you feel skeptical about my answer, then you should plug -2 back into the equation to check if it's correct. And it's correct for me when I did it.

7 0

3 years ago

For f(x)=4x+1 and g(x)=x^2-5 find (g/f)(x)

Ipatiy [6.2K]

$f(x)=4x+1\\\\g(x)=x^2-5\\\\(g/f)(x)=\dfrac{g(x)}{f(x)}=\dfrac{x^2-5}{4x+1}$

6 0

2 years ago

Read 2 more answers

In the game of blackjack played with one deck, a player is initially dealt 2 different cards from the 52 different cards in the

Volgvan

Answer:

$P =4.83\%$

Step-by-step explanation:

First we calculate the number of possible ways to select 2 cards an ace and a card of 10 points.

There are 4 ace in the deck

There are 16 cards of 10 points in the deck

To make this calculation we use the formula of combinations

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the total number of letters and r are chosen from them

The number of ways to choose 1 As is:

$4C1 = 4$

The number of ways to choose a 10-point letter is:

$16C1 = 16$

Therefore, the number of ways to choose an Ace and a 10-point card is:

$4C1 * 16C1 = 4 * 16 = 64$

Now the number of ways to choose any 2 cards from a deck of 52 cards is:

$52C2 =\frac{52!}{2!(52-2)!}$

$52C2 = 1326$

Therefore, the probability of obtaining an "blackjack" is:

$P = \frac{4C1 * 16C1}{52C2}$

$P = \frac{64}{1326}$

$P = \frac{32}{663}$

$P =0.0483$

$P =4.83\%$

4 0

2 years ago

Read 2 more answers