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Anna [14]
3 years ago
11

Pls help fast i dont get this

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0
For the first one it is the fourth one 15/x
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What does negative 5 over 2 < −1 indicate about the positions of negative 5 over 2 and −1 on the number line?
quester [9]
This indicates that 5/2 is less than -1 on the number line.
4 0
3 years ago
Help ASAP
horrorfan [7]

Answer:

p=\frac{181}{301}

Step-by-step explanation:

30100 have dogs, 18100 have cats.

The question simply asks for a union scenario thus the law of AND & OR is applicable.

Therefore:-Those who have both cats and dogs partially have cats.

P(X=both \ cat \ and \ dog)=\frac{18100}{30100}\\p=\frac{181}{301}

8 0
3 years ago
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Answer for the points<br> 6 − (9 − 2) + 3 × 6
AfilCa [17]

Answer:

17

Step-by-step explanation:

USING BIDMAS (Brackets Indices Division Multiplication Addition Subtraction)

6 − (9 − 2) + 3 × 6

9-2=7

3x6=18

6-7+18=17

8 0
3 years ago
Can anyone help me solve the boxes that are blank? <br> I really appreciate it!
Readme [11.4K]

Answer:

わたしは、あなたを愛しています Zesto

5 0
3 years ago
Compound interest In Exercise,$3000 is invested in an account at interest rate r,compounded continuously.Find the time required
xenn [34]

Answer:

(a) 8.15

(b) 12.92

Step-by-step explanation:

Given: P = $3000, r = 0.085

                A = Pe^{rt}

Where

A is the Amount

P is the Principal

r is the rate

t is the time

(a) For the amount to double, A = 2 × P

               A = 2 × $3000

               A = $6000

               6000 = 3000e^{0.085t}

               \frac{6000}{3000} = e^{0.085t}

               2 = e^{0.085t}

Take log_{e} of both sides

               log_{e}2 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln2 = 0.085t

               t = \frac{ln2}{0.085}

               t = \frac{0.693}{0.085}

               t = 8.15

(b) For the amount to double, A = 3 × P

               A = 3 × $3000

               A = $9000

               9000 = 3000e^{0.085t}

               \frac{9000}{3000} = e^{0.085t}

               3 = e^{0.085t}

Take log_{e} of both sides

               log_{e}3 = log_{e}e^{0.085t}

But log_{e}e = 1

            ∴ ln3 = 0.085t

               t = \frac{ln3}{0.085}

               t = \frac{1.0986}{0.085}

               t = 12.92

5 0
3 years ago
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