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babymother [125]
3 years ago
13

A magician asks two volunteers to each draw a card from a standard deck of cards. What is the probability that the first card is

a heart and the second card is a diamond
Mathematics
2 answers:
mars1129 [50]3 years ago
4 0

Answer:

6.37%

Step-by-step explanation:

A deck of cards have 52 cards.  There are 4 suits of 13 card each, those suits are Hearts, Clubs, Diamond and Spades.

The probability that the first card is a heart is:

P(Hearts) = \frac{13}{52}

Now, the probabily that the second card is a diamond is:

P(Diamond | First card is Heart) = \frac{13}{51}

The Probability that the first card is a heart and the second one a diamond is given by:

P(Hearts)×P(Diamond | First card is Heart)

= \frac{13}{52}\frac{13}{51}

= 6.37%

serg [7]3 years ago
4 0

Answer:

6.37 %

Step-by-step explanation:

First card is 13/52 , the second card is 13/51.

So the probability is (13/52 × 13/51) = 6.37 %

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Find the area of the following shape.
ad-work [718]

Answer:

57 units^2

Step-by-step explanation:

First find the area of the triangle on the left

ABC

It has a base AC which is  9 units and a height of 3 units

A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5

Then find the area of the triangle on the right

DE

It has a base AC which is  6 units and a height of 1 units

A = 1/2 bh = 1/2 ( 6) *1  = 3

Then find the area of the triangle on the top

It has a base AC which is  3 units and a height of 3 units

A = 1/2 bh = 1/2 ( 3) *3  = 9/2 = 4.5

Then find the area of the rectangular region

A = lw = 6*6 = 36

Add them together

13.5+3+4.5+36 =57 units^2

5 0
2 years ago
Read 2 more answers
Could use help with this one! Will give thanks and brainliest to correct answer
cluponka [151]
I believe the answer is A
5 0
2 years ago
Read 2 more answers
If the first chapter of a certain book is 28 pages long and makes up 4% of the book, how many pages does the entire book have?
Schach [20]

Answer:

700 pages

Step-by-step explanation:

I first found out how many pages were in 1% so I divided 28 by 4.  

I got 7 so I multiplied it by 100 and 700 was the answer.

Basically:

28÷4 = 7

7 x 100 = 700

I hope that kinda made sense!

8 0
3 years ago
Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan
Lunna [17]

Answer:

(a) Null Hypothesis, H_0 : \mu \leq 41  

    Alternate Hypothesis, H_A : \mu > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let \mu = <u><em>mean sunspot activity during the Spanish colonial period.</em></u>

(a) Null Hypothesis, H_0 : \mu \leq 41     {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, H_A : \mu > 41     {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                            T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean = 47

            σ = population standard deviation = 35

            n = sample of periods from Spanish colonial times = 40

So, <em><u>the test statistics</u></em>  =  \frac{47-41}{\frac{35}{\sqrt{40} } }

                                      =  1.08

(b) The value of z test statistics is 1.08.

(c) <u>Now, the P-value of the test statistics is given by;</u>

                P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

                              = 1 - 0.8599 = <u>0.1401</u>

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0
3 years ago
A cube with each face a different colour will fit exactly into a box in which it is packaged. In how many ways can the cube be p
dmitriy555 [2]

Answer:

362880 times

I hope this helps

4 0
2 years ago
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