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Andrei [34K]
3 years ago
13

Question 3 of 10

Mathematics
2 answers:
12345 [234]3 years ago
8 0

Answer:

F. and D.

Step-by-step explanation:

square root of 81 is 9 because 9 is a number which produces a specified quantity when multiplied by itself.

andreyandreev [35.5K]3 years ago
6 0
The answer should be 9 if I’m not mistaken
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Choose the equation that represents a line that passes through points (-1, 2) and (3, 1).
oksian1 [2.3K]

Answer:

<h2>B. x + 4y = 7</h2>

Step-by-step explanation:

\text{The point-slope form of an equation of a line:}\\\\y-y_1=m(x-x_1)\\\\m-slope\\\\\text{The formula of a slope:}\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\==============================

\text{We have the points (-1, 2) and (3, 1). Substitute:}\\\\m=\dfrac{1-2}{3-(-1)}=\dfrac{-1}{4}=-\dfrac{1}{4}\\\\\text{Put the value of a slope and the coordinates of the point (3, 1) }\\\text{to the equation of a line:}\\\\y-1=-\dfrac{1}{4}(x-3)\\\\\text{Convert to the standard form}\ Ax+By=C:\\\\y-1=-\dfrac{1}{4}(x-3)\qquad\text{multiply both sides by 4}\\\\4y-4=-(x-3)\\\\4y-4=-x-(-3)\qquad\text{add x to both sides}\\\\x+4y-4=3\qquad\text{add 4 to both sides}\\\\x+4y=7

8 0
4 years ago
Amira is writing a coordinate proof to show that the area of a triangle created by joining the midpoints of an isosceles triangl
Romashka [77]
Point R is the midpoint of FE¯¯¯¯¯ , so the coordinates of point R are (3a, b).

In △DEF , the length of the base, DF¯¯¯¯¯ , is
4a, and the height is 2b, so its area is
1/2×4a×2b = 4ab.

In △QRP , the length of the base, QR¯¯¯¯¯ , is
3a-a = 2a, and the height is b, so its area is 1/2×2a×b = ab .

Comparing the expressions for the areas proves that the area of the triangle created by joining the midpoints of an isosceles triangle is one-fourth the area of the larger isosceles triangle.
6 0
3 years ago
Read 2 more answers
Please help!!! How do you solve for x?<br> 6          3<br> ___ = __<br> x+2    4
dexar [7]
It's 6 because if you simplify 6 over 8 you get 3 over 4 because half of 6 is 3 and half of 8 is 4
7 0
4 years ago
Read 2 more answers
Tìm x : 2x^2-7x+3=0<br> giúp tui zới, please
Gnoma [55]
<h2>Solving Quadratic Equations with the Quadratic Formula</h2>

<h3>Answer:</h3>

x = 3 and x = \frac{1}{2}\\

<h3>Step-by-step Explanation: </h3>

Recall:

if we have a quadratic equation, ax^2 +bx +c = 0, where a, b and c are real numbers and a \neq 0, x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}.

Given:

2x^2 -7x +3 = 0

Solving for x:

x = \frac{-(-7) \pm \sqrt{(-7)^2 -4(2)(3)}}{2(2)} \\ x = \frac{-(-7) \pm \sqrt{49 -4(2)(3)}}{2(2)} \\ x = \frac{7 \pm  \sqrt{49 -24}}{4} \\ x = \frac{7 \pm \sqrt{25}}{4} \\ x = \frac{7 \pm 5}{4}

Solving with the positive value:

x = \frac{7 +5}{4} \\ x = \frac{12}{4} \\ x = 3

Solving with the negative value:

x = \frac{7 -5}{4} \\ x = \frac{2}{4} \\ x = \frac{1}{2}

7 0
3 years ago
Answer plsssss………………
vova2212 [387]

Answer:

The corresponding angles theorem works for cases where we have two parallel lines intersecting another line.

Two lines are parallel if, at any point, the distance between these two lines is always the same.

Now, if we look at the image, we can see that the distance between the two horizontal lines changes (is smaller at the right and larger at the left)

Thus, these lines are not parallel.

Then the corresponding angles theorem can not be used here, and we have that:

∠9 ≠ ∠10

8 0
3 years ago
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