Answer:
The zeros of the function are;
x = 0 and x = 1
Step-by-step explanation:
The zeroes of the function simply imply that we find the values of x for which the corresponding value of y is 0.
We let y be 0 in the given equation;
y = x^3 - 2x^2 + x
x^3 - 2x^2 + x = 0
We factor out x since x appears in each term on the Left Hand Side;
x ( x^2 - 2x + 1) = 0
This implies that either;
x = 0 or
x^2 - 2x + 1 = 0
We can factorize the equation on the Left Hand Side by determining two numbers whose product is 1 and whose sum is -2. The two numbers by trial and error are found to be -1 and -1. We then replace the middle term by these two numbers;
x^2 -x -x +1 = 0
x(x-1) -1(x-1) = 0
(x-1)(x-1) = 0
x-1 = 0
x = 1
Therefore, the zeros of the function are;
x = 0 and x = 1
The graph of the function is as shown in the attachment below;
It would be B. 68
I hope this help!
Answer:
3x^2 + 7xy + 5
Step-by-step explanation:
Answer:

Step-by-step explanation:
We are asked to find the equation of a line in slope-intercept form. We are given a point and a slope, so we can use the point-slope formula.

In this formula, m is the slope and (x₁, y₁) is the point the line passes through. The slope of the line is 8 and it passes through the point (1, -6). Therefore,
Substitute these values into the formula.

Remember that 2 back to back subtraction signs are the same as an addition sign.

The line must be in slope-intercept form or y=mx+b (m is the slope and b is the y-intercept. We must isolate the variable y on one side of the equation. First, distribute on the right side of the equation. Multiply each term inside the parentheses by 8.



6 is being added to y. The inverse operation of addition is subtraction, so we subtract 6 from both sides of the equation.



The equation of the line in slope-intercept form is <u>y=8x-14</u>. The slope is 8 and the y-intercept is -14.
Answer:
Anticlockwise 60°
Step-by-step explanation:
Let my starting point be 0°
Turning to the right(clockwise)40° = 0° + 40° = 40°
I am now at 40° to the right of my starting point.
Turning to the left(anticlockwise) 70° = 40° - 70° = -30°
I am now 30° to the left of my starting point.
Turning to the right 90° = -30° + 90° = 60°
I am 60° to the right of my starting point.
To go back to the startoing point(0°), I should go to the left(anticlockwise) by 60°
This is a change of -60°
-Chetan K