Shop sells bagles for 5 per dozen how much bagles can you buy for 50

Use the five-step plan to solve the following problem. Joey has nickels and dimes in his pocket. The number of dimes is 3 times

HACTEHA [7]

Not sure what the 5 step plan is but

Joey has 11 nickels
so from "<span>The number of dimes is 3 times the number of nickels."
we know joey has 33 dimes.
11 nickels is 55 cents. 33 dimes is 3 dollars and 30 cents
in total 3 dollars and 85 cents</span>

5 0

3 years ago

5 is what percentage of 10 question: now do I divide 5 divided by 10 equals 0.5 then do I multiply 0.5 by 100 or divide 0.5 by 1

lara31 [8.8K]

Answer:

50%

Step-by-step explanation:

5 question is what percentage of 10 question

Step 1: Divide 5 by 10

5/10 = 0.5

Step 2: multiply 0.5 by 100

0.5 × 100

= 50%

Therefore, percentage of 5 questions out of 10 questions is 50%

3 0

3 years ago

Identify the sequence as arithmetic geometric or neither -8, -3, 6, 11, -22

melomori [17]

Answer:

Neither

Step-by-step explanation:

Check if it's arithmetic:

-8, -3, 6, 11, -22

+5 +6 +5 -33

Nope

Check if geometric:

-8, -3, 6, 11, -22

*3/8 *-2 *11/6 *-2

Nope

So it's neither

5 0

3 years ago

What is the awnser to −35+7+(−15)

Wewaii [24]

Answer:

-43

Step-by-step explanation:

-35 + 7 + (-15)

-35 + 7 - 15

-50 + 7

<u>= -43</u>

4 0

2 years ago

Read 2 more answers

In a study of 420,095 Danish cell phone users, 135 subjects developed cancer of the brain or nervous system (based on data from

Maksim231197 [3]

Answer:

$z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654$

$p_v =2*P(Z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.005$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

Step-by-step explanation:

1) Data given and notation

n=420095 represent the random sample taken

X=135 represent the subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

$\hat p=\frac{135}{420095}=0.0003214$ estimated proportion of subjects developed cancer of the brain or nervous system (based on data from the Journal of the National Cancer Institute as reported in USA Today)

$p_o=0.00034$ is the value that we want to test

$\alpha=0.005$ represent the significance level

Confidence=99.5% or 0.995

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the brain or nervous system at a rate that is different from the rate of 0.0340% :

Null hypothesis: $p=0.00034$

Alternative hypothesis: $p \neq 0.00034$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.0003214 -0.00034}{\sqrt{\frac{0.00034(1-0.00034)}{420095}}}=-0.654$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.005$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(Z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.005$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say that the true proportion not differs significantly from the specified value of 0.00034 or 0.034%.

4 0

3 years ago