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blondinia [14]
2 years ago
7

What is the next patter for 4.5,9,13.5,18

Mathematics
1 answer:
abruzzese [7]2 years ago
4 0
22.5 because its counting by 4.5
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Select all the equations on which the point (10,0) lies
lora16 [44]
There is no answer choices
5 0
3 years ago
Read 2 more answers
Pls help need it done pls
Harman [31]

Answer:

1/4 +m = 2/3

Step-by-step explanation:

3 0
3 years ago
The Eiffel Tower is 324 m tall. If a tourist is looking at it from 100 m away from the base,
romanna [79]

Answer:

80,94º

Step-by-step explanation:

What I've done is, first draw a triangle with a 90º angle and write down the height (324m) and the tourist's distance (100m).

So I calculated the tangent of the angle of the tourist.

The formula is tan=Oposite side/adjacent

tan=\frac{opposite side}{adjacent}

tan=\frac{324}{100} =3.24

And now with your calculator you press "shift" and "tan". Then introduce 3,24 and it will give you the result (80,94º).

I hope it helped.

4 0
2 years ago
26. Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics
hjlf

The test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

<h3>What are null hypotheses and alternative hypotheses?</h3>

In null hypotheses, there is no relationship between the two phenomenons under the assumption or it is not associated with the group. And in alternative hypotheses, there is a relationship between the two chosen unknowns.

Students who take a statistics course are given a pre-test on the concepts and skills for the first chapter of a statistics course.

Then they are given a post-test once the professor has concluded lecturing on the material.

Pre-test and post-test scores for 4 students in an elementary statistics class are given below.

Then we have

\mu _d = \mu _{post} - \mu _{pre}

Then the null hypotheses and alternative hypotheses will be

H₀: \mu _d = 0

Hₐ: \mu _d > 0

Then the test statistic will be

\rm \overline{x} _d = \dfrac{\Sigma x_d}{n} = \dfrac{15+12+10+1}{4}\\\\\overline{x} _d = 9.5

Then

\rm S_d = 6.02

The test statistic value is given by

\rm t = \dfrac{\overline{x} _d }{\dfrac{S_d}{\sqrtn}} \\\\t = \dfrac{9.5}{\dfrac{6.02}{\sqrt4}}\\\\t = 3.16

Since this is a right-tailed test, so the critical value is given by

\rm t_{n-1}(\alpha ) = t_3 (0.05) = 2.353

Since the test statistic value lies to the right of the critical value. So we have sufficient evidence to reject the null hypothesis.

Hence, we can conclude that \mu _d > 0 that is test scores have improved.

More about the null hypotheses and alternative hypotheses link is given below.

brainly.com/question/9504281

#SPJ1

7 0
1 year ago
Which number is prime... 11. 49. 51. 81
Rzqust [24]
The answer to your question is 11
8 0
3 years ago
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