3 years ago

How can I find the solution of this deferential equation (x) '' + kx =0

Mathematics

1 answer:

agasfer [191]3 years ago

8 0

Answer:

Step-by-step explanation:

This is a second order linear differential equation . Im afraid Ive forgotten the method. Any good calculus book would help with this.

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A and B are points on a line that has the slope 2. The abscissa of B exceeds the abscissa of A by 3.5. State the relationship of

Troyanec [42]

Answer:

The ordinate of B exceeds the ordinate of A by 7

Step-by-step explanation:

Let

A(x1,y1),B(x2,y2)

where

x1 is the abscissa of A

x2 is the abscissa of B

y1 is the ordinate of A

y2 is the ordinate of B

we know that

$m=\frac{y2-y1}{x2-x1}$

$m=2$

$2=\frac{y2-y1}{x2-x1}$ -----> equation A

$x2=x1+3.5$ ----> equation B

substitute equation B in equation A

$2=\frac{y2-y1}{x1+3.5-x1}$

$2=\frac{y2-y1}{3.5}$

$7=y2-y1$

$y2=y1+7$

therefore

The ordinate of B exceeds the ordinate of A by 7

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Answer:

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How can I find the solution of this deferential equation (x) '' + kx =0​

How can I find the solution of this deferential equation (x) '' + kx =0