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3 years ago

14

How can I find the solution of this deferential equation (x) '' + kx =0

1 answer:

agasfer [191]3 years ago

8 0

Answer:

Step-by-step explanation:

This is a second order linear differential equation . Im afraid Ive forgotten the method. Any good calculus book would help with this.

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I need help with number 4, find the area, thank you

Westkost [7]

Answer:

142.5cm2 if it's correct I would appreciciate a brainliest

Step-by-step explanation:

15x19=285

285/2=142.5

5 0

3 years ago

Read 2 more answers

An airplane is flying at an elevation of 3,750 feet and lands on an airstrip 250 below sea level. What is the difference between

stiv31 [10]

Answer:

4000 feet

Step-by-step explanation:

GIVEN: An airplane is flying at an elevation of $3,750\text{ feet}$ and lands on an airstrip $250\text{ feet}$ below sea level.

TO FIND: What is the difference between these two elevation.

SOLUTION:

Elevation of airplane while flying $=3750\text{ feet}$

As airstrip is below sea level,

Elevation airplane while on airstrip $=-250\text{ feet}$

Difference between elevations $=\text{elevation when flying}-\text{elevations while on airstrip}$

$=3750-(-250)$

$=3750+250 \text{feet}$

$=4000\text{ feet}$

Hence difference between elevations is 4000 feet.

3 0

3 years ago

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What is xz and xy?.....................

Fittoniya [83]

It is the angles and also how long that segment of the triangle

6 0

3 years ago

You've deposited $5,000 into a Michigan Education Savings Program (a 529 college savings program) for your daughter who will be

vivado [14]

Answer:

Ans. the annual rate of return, in order to turn $5,000 into $24,000 in 15 years is 11.02% annual.

Step-by-step explanation:

Hi, well, in order to find the value of the interest rate of return, we need to solve for "r" the following equation,

$Future Value=PresentValue(1+r)^{n}$

Where:

n= years (time that the money was invested)

r=annual rate of return (Decimal)

So, let´s see the math of this.

$24,000=5,000(1+r)^{15}$

$\frac{24,000}{5,000} =(1+r)^{15}$

$\sqrt[15]{\frac{24,000}{5,000} } =1+r$

$\sqrt[15]{\frac{24,000}{5,000} } -1=r$

$r=0.11023$

So the annual rate of return that turns $5,000 into $24,000 in 15 years is 11.02%.

N=15; PV=5,000; FV=24,000; PMT=N.A; I/Y=11.02% P/Y=N.A

Best of Luck.

3 0

3 years ago

What is the following product? Assume x greater-than-or-equal-to 0

Readme [11.4K]

Which is the following product? Assume x ≥ 0

$\sqrt[3]{x^{2}} \times\sqrt[4]{x^{3}}$

A. $x\sqrt{x}$

B. $\sqrt[12]{x^{5}}$

C. $x\sqrt[12]{x^{5}}$

D. $x^{6}$

Answer:

C. $x\sqrt[12]{x^{5}}$

Step-by-step explanation:

NOTE : $\sqrt[n]{x^{m}}=x^{\frac{m}{n}}$

$x^{a}\times x^{b}=x^{a+b}$

$\sqrt[3]{x^{2}} \times\sqrt[4]{x^{3}}$

$=x^{\frac{2}{3}}\times x^{\frac{3}{4}}$

$=x^{\frac{2}{3}+\frac{3}{4}}$

$=x^{\frac{2\times4+3\times3}{12}}$

$=x^{\frac{8+9}{12}}$

$=x^{\frac{17}{12}}$

$=x^{\frac{12+5}{12}}$

$=x^{\frac{12}{12}+\frac{5}{12}}$

$=x^{1+\frac{5}{12}}$

$=x\times x^{\frac{5}{12}}$

$=x\sqrt[12]{x^{5}}$

3 0

3 years ago

Read 2 more answers