How can I find the solution of this deferential equation (x) '' + kx =0

Mathematics

1 answer:

agasfer [191]2 years ago

8 0

Answer:

Step-by-step explanation:

This is a second order linear differential equation . Im afraid Ive forgotten the method. Any good calculus book would help with this.

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My questions are in the picture please help

Marrrta [24]

21.

So to solve for the value of a variable in an equation, you would need to isolate x on one side. The first thing you have to do is multiply 2 and (x + 7) together, which can be rewritten as 2(x) + 2(7). After multiplying, your equation would be: $2x+14+3x=12$ , or A.

22.

So the rule with multiplying exponents with the same base is to add the exponents together, and the rule with dividing exponents with the same base is to subtract the exponents. Your equation will be simplified as such:

$4^{(3+4)-9}\\ 4^{7-9}\\ 4^{-2}$

Now the rule with converting negative exponents into fractions is $x^{-m}=\frac{1}{x^m}$ . In this case, 4^-2 would turn into $\frac{1}{4^2}$ , or C, which is your final answer.