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kari74 [83]
3 years ago
5

Can someone help me asap?​

Mathematics
2 answers:
julia-pushkina [17]3 years ago
5 0

Answer:

square a = 7

square b = 50

square c = 7

sqaure d = 6

7 x 56 = (7 x 50) + (7 + <u>6</u>)

<u>350</u> +  <u>42</u> =  <u>392</u>

7 x 56 = <u>392</u>

Leni [432]3 years ago
3 0

Answer:

U NEED TO KNOW PEMDAS SO U CAN ANSWER IT

Step-by-step explanation:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

you sort first, multiplication you do and next parenthesis and the last plus,

if you still don't understand you just take care I told you to do it to all viewers if u understand well like it thanks

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Helpp ludzie pomocy bo gram cały czas na lekcjach (xd) a moja matka przyszła do haułpy ​
leonid [27]

yes yes yes yes yes yes neight

Step-by-step explanation:

1234567891

8 0
2 years ago
These polygons are similar. Which similarity statement is correct?
vodomira [7]

Answer:

A B C D is similar to F G H E

Step-by-step explanation:


Here we can see that

 A= F= 110 degrees

B = G= 70 degrees

C= H = 110 degrees

D= E = 70 degrees

Therefore

A B C D is similar to F G H E

so the option 3rd  correct.



5 0
3 years ago
Read 2 more answers
What is the value of x?<br><br><br><br> Enter your answer in the box.
pshichka [43]
Hello!

The sum of all angle measures in a heptagon in 900°. We will subtract all of these angles from 900 to find our answer.

900-146-122-142-140-110-142=98

x=98°

I hope this helps!
4 0
2 years ago
Read 2 more answers
An adult brain is about 140 mm wide and divided into two sections (called "hemispheres" although the brain is not truly spherica
Sedbober [7]

Answer: 3.61×10^5 A

Step-by-step explanation: Since the brain has been modeled as a current carrying loop, we use the formulae for the magnetic field on a current carrying loop to get the current on the hemisphere of the brain.

The formulae is given below as

B = u×Ia²/2(x²+a²)^3/2

Where B = strength of magnetic field on the axis of a circular loop = 4.15T

u = permeability of free space = 1.256×10^-6 mkg/s²A²

I = current on loop =?

a = radius of loop.

Radius of loop is gotten as shown... Radius = diameter /2, but diameter = 65mm hence radius = 32.5mm = 32.5×10^-3 m = 3.25×10^-2m

x = distance of the sensor away from center of loop = 2.10 cm = 0.021m

By substituting the parameters into the formulae, we have that

4.15 = 1.256×10^-6 × I × (3.25×10^-2)²/2{(0.021²) + (3.25×10^-2)²}^3/2

4.15 = 13.2665 × 10^-10 × I/ 2( 0.00149725)^3/2

4.15 = 1.32665 ×10^-9 × I / 2( 0.000058)

4.15 × 2( 0.000058) = 1.32665 ×10^-9 × I

I = 4.15 × 2( 0.000058)/ 1.32665 ×10^-9

I = 4.80×10^-4 / 1.32665 ×10^-9

I = 3.61×10^5 A

3 0
3 years ago
A family of two adults and three children goes to a play admission costs eight dollars per adult and $5 per child. What expressi
Sidana [21]
D = adult
c = child
t = total admission cost

t = 8d + 5c

t = 8(2) + 5(3) = $31
5 0
3 years ago
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