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kodGreya [7K]
4 years ago
15

How do you solve 6x^2 +12x-48=0 by completing the square?

Mathematics
1 answer:
Likurg_2 [28]4 years ago
8 0

Answer:

x = -4  and x = 2

Through the Completing the Square process below:

Step-by-step explanation:

solve 6x^2 +12x-48=0

first divide out the 6

x^2 + 2x - 8 = 0

Then use the Diamond method:

-8 = -2*4 ,   and  -2 + 4 = 2

so

x^2 - 2x + 4x - 8 = 0

x(x - 2) + 4*(x -2) = 0

(x + 4)(x - 2) = 0

so, solve  x + 4 = 0    and  (x - 2) = 0

x = -4  and x = 2

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Solutions 

1) Find the least common denominator of 7/10 and 1/5. 
10: 10 
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2) Make the denominator of 1/5 to 10. Multiply numerator and denominator by 2.

1 x 2 = 2 
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3) New fraction 
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4) Add 
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9/10 is answer 

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3 years ago
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