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3 years ago

Describe the rule for the rotation.

Mathematics

1 answer:

finlep [7]3 years ago

4 0

Answer:

Step-by-step explanation:

If you draw a line from the origin (0,0) to L ( the original point ) and a different line from the origin to the image L' you can see the angle of rotation as being

90 degrees and that the rotation is clockwise.

the rule is (x, y) become ( y, -x)

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Simplify Which of the following is correct?

aalyn [17]

The difference between mixed numbers gives:

-5¹/₆ - (-8¹/₂) = 3¹/₃

So the correct option is the third one.

<h3 /><h3>How to get the difference between mixed numbers?</h3>

Here we want to compute the difference between two mixed numbers.

First, remember that we can rewrite those as:

-5¹/₆ = (-5 - 1/6)

-8¹/₂ = (-8 - 1/2)

Now, let's go to the difference:

-5¹/₆ - (-8¹/₂)

First you can see that there are two negative signs together, so it is equivalent to a positive sign:

-5¹/₆ - (-8¹/₂) = -5¹/₆ + 8¹/₂

Now we can replace the mixed numbers to get:

-5¹/₆ + 8¹/₂ = (-5 - 1/6) + (8 + 1/2) = (8 - 5) + (1/2 - 1/6) = (3 + 2/6) = 3 + 1/3

And that can be rewritten to:

3 + 1/3 = 3¹/₃

Which is completely simplified.

So we conclude that the correct option is the third one, counting from the top.

If you want to learn more about mixed numbers:

brainly.com/question/1746829

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6 0

2 years ago

Write a linear equation in standard form that satisfies the given set of conditions. X-intercept: 3, y-intercept: 5

Artyom0805 [142]

The linear equation in standard form is $y=\frac{-5}{3}x +5$ .

<h3>Linear Function</h3>

An equation can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=7x+2. Where:

a= the slope. It can be calculated for $\frac{\Delta x }{\Delta y}$ .

b= the constant term that represents the y-intercept.

The question gives: X-intercept:3 and y-intercept: 5. Then,

The x-intercept is the point that y=0, then the x-intercept point is (3,0).
The y-intercept is the point that x=0, then the x-intercept point is (0,5).

With this information, you can find the slope (a).

$a=\frac{\Delta y }{\Delta x}= \frac{0-5}{3-0} =\frac{-5}{3}$

The question gives the coefficient b since it gives the y-intercept=5.

Therefore the linear equation is : $y=\frac{-5}{3}x +5$ .

Read more about the linear equations here:

brainly.com/question/2030026

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4 0

2 years ago

Andrea bought tacos from a food truck and left a 2 5 % 25%25, percent tip of $ 2 . 0 0 $2.00dollar sign, 2, point, 00. What was

Bingel [31]

Let us say the original price of taco before tip was x dollars.

Percentage of tip given =25 %

Amount of tip given = $2

Now we can say that 25 % of total amount = 2 dollars.

Making an equation,

$0.25x =2$

Now we have to solve for x, so dividing both sides by 0.25,

x= 8

Answer : The original price of tacos before tip was $8.

5 0

3 years ago

Read 2 more answers

Suppose a geyser has a mean time between irruption’s of 75 minutes. If the interval of time between the eruption is normally dis

lesya [120]

Answer:

(a) The probability that a randomly selected Time interval between irruption is longer than 84 minutes is 0.3264.

(b) The probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is 0.0526.

(c) The probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is 0.0222.

(d) The probability decreases because the variability in the sample mean decreases as we increase the sample size

(e) The population mean may be larger than 75 minutes between irruption.

Step-by-step explanation:

We are given that a geyser has a mean time between irruption of 75 minutes. Also, the interval of time between the eruption is normally distributed with a standard deviation of 20 minutes.

(a) Let X = <u><em>the interval of time between the eruption</em></u>

So, X ~ Normal( $\mu=75, \sigma^{2} =20$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean time between irruption = 75 minutes

$\sigma$ = standard deviation = 20 minutes

Now, the probability that a randomly selected Time interval between irruption is longer than 84 minutes is given by = P(X > 84 min)

P(X > 84 min) = P( $\frac{X-\mu}{\sigma}$ > $\frac{84-75}{20}$ ) = P(Z > 0.45) = 1 - P(Z $\leq$ 0.45)

= 1 - 0.6736 = <u>0.3264</u>

The above probability is calculated by looking at the value of x = 0.45 in the z table which has an area of 0.6736.

(b) Let $\bar X$ = <u><em>sample time intervals between the eruption</em></u>

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean time between irruption = 75 minutes

$\sigma$ = standard deviation = 20 minutes

n = sample of time intervals = 13

Now, the probability that a random sample of 13 time intervals between irruption has a mean longer than 84 minutes is given by = P( $\bar X$ > 84 min)

P( $\bar X$ > 84 min) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{84-75}{\frac{20}{\sqrt{13} } }$ ) = P(Z > 1.62) = 1 - P(Z $\leq$ 1.62)

= 1 - 0.9474 = <u>0.0526</u>

The above probability is calculated by looking at the value of x = 1.62 in the z table which has an area of 0.9474.

(c) Let $\bar X$ = <u><em>sample time intervals between the eruption</em></u>

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean time between irruption = 75 minutes

$\sigma$ = standard deviation = 20 minutes

n = sample of time intervals = 20

Now, the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is given by = P( $\bar X$ > 84 min)

P( $\bar X$ > 84 min) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{84-75}{\frac{20}{\sqrt{20} } }$ ) = P(Z > 2.01) = 1 - P(Z $\leq$ 2.01)

= 1 - 0.9778 = <u>0.0222</u>

The above probability is calculated by looking at the value of x = 2.01 in the z table which has an area of 0.9778.

(d) When increasing the sample size, the probability decreases because the variability in the sample mean decreases as we increase the sample size which we can clearly see in part (b) and (c) of the question.

(e) Since it is clear that the probability that a random sample of 20 time intervals between irruption has a mean longer than 84 minutes is very slow(less than 5%0 which means that this is an unusual event. So, we can conclude that the population mean may be larger than 75 minutes between irruption.

8 0

3 years ago

How many liters are there in a tank of volume 7.32m³?

Ivenika [448]

Answer: 3 liters in a tank of volume 7.32m^3

Step-by-step explanation:

7 0

2 years ago