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Alekssandra [29.7K]
3 years ago
14

The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypote

nuse is (??) units, and the area of the triangle is (??) square units. (Hint: Use the Pythagorean theorem.)
Mathematics
2 answers:
nirvana33 [79]3 years ago
3 0
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
4vir4ik [10]3 years ago
3 0
A=1/2 b times h
1/2(3 times 4)
=6 is the correct answer

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horsena [70]

Answer:

x=26

Step-by-step explanation:

by definition of alternate exterior angle rule 8x -71 = 5x +7

What you want to do is get your X's on one side I recommend subtracting 5x so that you don't have to deal with negative values.

8x-5x-71=5x-5x+7

3x-71=7

add 71 to both sides the goal now is trying to get by itself

3x-71+71=7+71

3x=78

now divide both sides by 3

3x/3=78/3

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3 years ago
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Write the equation of the line that passes through (3, 4) and (2, −1) in slope-intercept form.
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(3,4)(2,-1)
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slope(m) = 5
u can use either of ur points...(3,4)...x = 3 and y = 4
now we sub and find b, the y int
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4 = 15 + b
4 - 15 = b
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Answer:

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81x^2-9x-10

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