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xxTIMURxx [149]
4 years ago
7

You deposit $6,000 in the bank. The account earns 7.5% simple interest. How much will be in the account in 2 years?

Mathematics
1 answer:
ivolga24 [154]4 years ago
3 0
The answer is 900, i hope its helps
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2a^2-5a=3 solve by factoring
Amiraneli [1.4K]

Answer:

a=−1/2, 3

3Step-by-step explanation:

6 0
3 years ago
Find the circumference of each circle
cestrela7 [59]

Step-by-step explanation:

Multiply the radius by 2 to get the diameter. Multiply the result by π, or 3.14 for an estimation. That's it; you found the circumference of the circle

And then for diameter you have to Multiply the diameter by π, or 3.14. The result is the circle's circumference.

8 0
3 years ago
Two Aps have the same first and last terms .The first Ap has 21 terms with a common difference of nine how many terms has the ot
Pani-rosa [81]

Answer:

46 terms

Step-by-step explanation:

a₁=b, a₂₁= bₙ, d₁=9, d₂=4

n=?

---------------

a₂₁= a₁+20d₁= a₁+20*9= a₁+180

bₙ= b₁+(n-1)d₂= a₁+4(n-1)

a₁+4(n-1)=a₁+180

4(n-1)=180

n-1= 180/4

n-1= 45

n=46

7 0
3 years ago
From a point 18 feet from the base of a tower, a wire is stretched to an attachment 40 feet up the tower. A right triangle with
Tamiku [17]
To find the length of the wire, use the Pythagorean theorem

a^2 + b^2 = c^2
18^2 + 40^2 = c ^2
324 + 1600 = c^2
1924 = c^2
44 = c

The wire is approximately 44 feet.
8 0
4 years ago
Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1
defon
I'm guessing the series is supposed to be

\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}

By the ratio test, the series converges if the following limit is less than 1.

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|

The first n terms in the numerator's denominator cancel with the denominator's denominator:

\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|

|x^n| also cancels out and the remaining factor of |x| can be pulled out of the limit (as it doesn't depend on n).

\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0

which means the series converges everywhere (independently of x), and so the radius of convergence is infinite.
3 0
4 years ago
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