Area = (1/2) * 4 * 5 = 10 cm²
Answer:
55R^3
Step-by-step explanation:
V= L X H X D
V= 4 X 5.5 X 2.5
V=55
Lets say we have a quadratic equation:
3x^2 + x + 0 = 0
Now, since if we add or subtract 0 from something, the original value stays the same, which means we can write the equation as 3x^2 + x = 0 and ignore the “+0”.
In these kinds of equations, you /can/ use the quadratic formula, but theres a much quicker way. If we factor 3x^2 + x, we get x(3x + 1) = 0. Here, x has two possible values — since the result of the multiplication is 0, that means that either one expression or the other must equal 0. In essence:
If x(3x+1) = 0 then x = 0 or 3x+1 = 0
One of the solutions is that x = 0. Lets find the other.
3x+1=0
3x= -1
x = -1/3
So x1 = 0 and x2 = -1/3. So basically you solve these equations using basic factorization. :)
Rewrite
(4)(3.63) * (10^4)(10^-4)
multiply
14.52 * (10^4)(10^-4)
multiplication of the coefficient is the addition of the exponent
so 4 -4 is 0
14.52
Hope this helps :)
