Answer:
(B) 5/6 ·13÷4
(C) 5/6 ÷4·13
(D) 5/6 · 13/4
Step-by-step explanation:
Amount of paint per can = ![\[\frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
Number of cans used to paint 4 cars = 13
Total amount of paint used for 4 cars = ![\[13 * \frac{5}{6}\]](https://tex.z-dn.net/?f=%5C%5B13%20%2A%20%5Cfrac%7B5%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{13 * 5}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B13%20%2A%205%7D%7B6%7D%5C%5D)
liters.
= ![\[\frac{65}{6}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%5C%5D)
liters.
Total amount of paint used for 1 car = ![\[\frac{65}{6} \div 4\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B6%7D%20%5Cdiv%204%5C%5D)
liters.
= ![\[\frac{65}{24}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B65%7D%7B24%7D%5C%5D)
liters.
Of the given options, option B,C and D correspond to the same value.
The answer is d: 16y^6/x^2
For the cylinder on the left-hand-side,
now, for the triangular prism on the right-hand-side,
notice is really just 2 triangles and 3 rectangles, stacked up to each other at the edges.
the triangles have a base of 4, and a height of 1.5.
the rectangle on the left and the one on the right is a 6x2.5 rectangle.
the rectangle at the bottom, is a 4x6 rectangle.
adding their areas, is the area of the prism,
![\bf \stackrel{two~triangles}{2\left[\cfrac{1}{2}(4)(1.5) \right]}+\stackrel{left-right~rectangles}{2(6\cdot 2.5)}+\stackrel{bottom~rectangle}{4\cdot 6} \\\\\\ 6~~+~~30~~+~~24](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7Btwo~triangles%7D%7B2%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%284%29%281.5%29%20%20%5Cright%5D%7D%2B%5Cstackrel%7Bleft-right~rectangles%7D%7B2%286%5Ccdot%202.5%29%7D%2B%5Cstackrel%7Bbottom~rectangle%7D%7B4%5Ccdot%206%7D%0A%5C%5C%5C%5C%5C%5C%0A6~~%2B~~30~~%2B~~24)
6 can go into 70 11 times without having a remainder so the 11 goes on the outside as your whole number. Then you have 4 left over to get to 70 so 4 becomes your numerator. The 6 stays as your denominator. So you have
Answer: d^9
Step-by-step explanation: i dunno it is what it is
