Answer:
11 h and 32 m is the answer
big d jit
dic dic dic dic dic dic dic di cidic idc
Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
Answer:
Step-by-step explanation:
<u>Let's simplify the inequality.</u>
- -6(m - 3) ≥ -24
- => -6m + 18 ≥ -24
- => 24 + 18 ≥ 6m
- => 42 ≥ 6m
- => 42/6 ≥ 6m/6
- => (7 ≥ m) = (m ≤ 7)
Option C is correct.
