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2 years ago

9

The probability distribution for the number of defects in a shipment of alarm clocks, based on past data, is given below. Find t

he expected number of defects in a shipment of alarm clocks.Number of defects, n: 0, 1, 2, 3, 4Probability of n defects: 0.82, 0.11, 0.04, 0.02, 0.01

1 answer:

Kay [80]2 years ago

3 0

Answer:

0.29

Step-by-step explanation:

Given :

n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4

P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01

The expected number of defect in a shipment can be obtained using the expected value formula :

Expected value, E(X) = Σx*p(x)

Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)

E(X) = 0.29

Hence, the expected number of defect in shipment is 0.29

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8 0

3 years ago

P³ = 1/8 please help me if anybody can .

ivanzaharov [21]

Answer:

$p= \dfrac{1}{2}$

Step-by-step explanation:

Given equation:

$p^3=\dfrac{1}{8}$

Cube root both sides:

$\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}$

$\implies p= \sqrt[3]{\dfrac{1}{8}}$

$\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:$

$\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}$

$\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:$

$\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad 1^a=1:$

$\implies p= \dfrac{1}{8^{\frac{1}{3}}}$

Rewrite 8 as 2³:

$\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}$

$\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:$

$\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}$

Simplify:

$\implies p= \dfrac{1}{2^{\frac{3}{3}}}$

$\implies p= \dfrac{1}{2^{1}}$

$\implies p= \dfrac{1}{2}$

3 0

1 year ago

Read 2 more answers

URGENTTT! CAN SOMEONE PLEASE HELP?

miskamm [114]

Answer:

Hey there!

We have tangent 29=h/400

Thus, tangent 29 times 400=h

h=221.7 feet.

The height of the kite is 221.7 feet.

Hope this helps :)

8 0

3 years ago

Same as my other question If one kilogram is 2.2 pounds. How many kilograms is 5.5 pounds?

Dvinal [7]

Answer:

2.5 kilograms

Step-by-step explanation:

Since 2 kilograms would be 4.4 pounds, subtract 4.4 from 5.5.

Then, you'd get 1.1

So, since 1.1 is half of 2.2, you can assume that 1.1 is half of a kilogram.

Then, add half a kilogram with 2 kilograms to get 2.5 kilograms.

Hope this helps!

3 0

3 years ago

SashulF [63]

Answer:

$n = -5$

Step-by-step explanation:

Given

$Digit = 0.000025$

Required

Rewrite using scientific notation, then find n

$Digit = 0.000025$

Express as fraction

$Digit =\frac{25}{1000000}$

This can be splitted to

$Digit = 25 * 10^{-6}$

The first number must be between 1 and 10; hence, 25 can be expressed as 2..5 * 10

$Digit = 2.5 * 10* 10^{-6}$

Apply law of indices

$Digit = 2.5 * 10^{1-6}$

$Digit = 2.5 * 10^{-5}$

Comparing n, the given options

$n = -5$

7 0

3 years ago