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den301095 [7]
4 years ago
8

Find

20%2B%207x%20-%205%20%29" id="TexFormula1" title="( {10x}^{2} - 11x + 8) + ( {2x}^{2} + 7x - 5 )" alt="( {10x}^{2} - 11x + 8) + ( {2x}^{2} + 7x - 5 )" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Inessa05 [86]4 years ago
4 0

Answer:

12x^2-4x+3

Step-by-step explanation:

Parentheses do not matter in this equation.

(10x^2-11x+8)+(2x^2+7x-5)=\\10x^2-11x+8+2x^2+7x-5=\\12x^2-11x+8+7x-5=\\12x^2-4x+8-5=\\12x^2-4x+3

Our answer is 12x^2-4x+3

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