Which is the graph of f(x) = 3(2/3)?
2 answers:
Answer:
Last graph on the right.
Step-by-step explanation:
Try substituting some values for x and see which graph is valid.
when x = 0, y = f(0) = 3 = 3 (1) = 3
When we compare this to the graphs, we immediately see that the first 2 are not correct because in those cases, when x=0, y = 6 (i.e not 3).
Next we try x = 1
when x = 1, y = f(1) = 3 = 3 (
) = 2
Comparing the graphs ones again, show that only the last graph has x=1 and y = 2.
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The statements that are true about the intervals of the continuous function are Options 2, 4 and 5
- f(x) ≤ 0 over the interval [0, 2].
- f(x) > 0 over the interval (–2, 0).
- f(x) ≥ 0 over the interval [2, ).
Looking at the values given, the intervals which satisfies the condition are known to be:
f(x)<=0 over the interval [0,2]
f(x)>0 over the interval (-2,0)
f(x)>=0 over the interval [2,∞)
Because:
Since the table with x and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .
Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)
Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]
When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)
When you look at the interval (-2,0) , the f(x) is positive and as such, f(x)>0 over the interval (-2,0)
Looking at the interval [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)
Therefore, Option 2, 4 and 5 are correct.
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