Part A.
Ashwin had a 4-cm cube.
volume of cube = side^3
volume = (4 cm)^3 = 64 cm^3
Ashwin has 64 small cubes.
We need to find the volumes of all prisms in Part A. Only prisms with at most 64 cm^3 volume can be the answer.
A. v = 2 * 4 * 7 = 28
B. v = 4 * 5 * 6 = 120
C. v = 5 * 5 * 4 = 100
D. v = 4 * 7 * 5 = 140
E. v = 3 * 5 * 4 = 60
Part A. answer: A, E
Part B.
Dora had a 5-cm cube.
volume of cube = side^3
volume = (5 cm)^3 = 125 cm^3
Dora has 125 small cubes.
We need to find the volumes of all prisms in Part B. Only prisms with at most 125 cm^3 volume can be the answer.
A. v = 3 * 3 * 8 = 72
B. v = 3 * 4 * 5 = 60
C. v = 6 * 6 * 4 = 144
D. v = 5 * 8 * 4 = 160
E. v = 3 * 5 * 4 = 60
Part B. answer: A, B, E
Width = w
length = w+2
f(w) =w(w+2) = w^2 + 2w.
Please, let me know whether the procedure is clear for you.
The answer is f(w)=w^2 + 2w.
Answer: The interest rate is .166%
Step-by-step explanation:
So what I did was divide $50(Amount at the end) by 6 (the number of months). Which would give me the amount of money he made per month ($8.333...). So then $8.333.../$5000(Total $) is .166...% (Interest rate)
Answer:
The inequality that represents the age of the group, "x", is: 
Step-by-step explanation:
To express this problem in an inequality we will attribute the age of the members on the group with the variable "x". There are two available information about "x", the first states that every member of the group is older than 17 years, therefore we can create a inequality based on that:

While the second data from the problem states that none of than is older than 54 years old, this implies that they can be at most that old, therefore the inequality that represents this is:

In order for both to be valid at the same time x must be greater than 17 and less or equal to 54, therefore we finally have:

Answer:

Step-by-step explanation:
<u>Formula for area of rectangle:</u>
= length × width
<u>Area of the smaller rectangle:</u>
length = 7
width = 6
= 7 × 6
= 42
<u>Area of the larger rectangle:</u>
length = 7 + 4 = 11
width = 6 + 2 = 8
= 11 × 8
= 88
<u>Area of the shaded region:</u>
= Area of the larger rectangle - Area of the smaller rectangle
= 88 - 42
= 46
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>