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WITCHER [35]
3 years ago
13

Look at the picture for the problem

Mathematics
2 answers:
emmasim [6.3K]3 years ago
7 0

w=40

because 2,400 divided by 60 is 40

Serjik [45]3 years ago
5 0

Answer:

w = 400

Step-by-step explanation:

2400 = lw

Divide the area by two.

2400 / 2 = 1200

Now this cannot be the answer since the length is longer than the width.

Divide 1200 by two again.

1200 = 600

Notice there are two choices that are the closest:

w = 800

w = 400

The latter choice would be the answer since again, the length is longer than width in terms of measurement

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Solve for x.<br> -5x + 12x - 8x = -24<br> x = _________a0
hichkok12 [17]

Answer:

x=24

Step-by-step explanation:

-5x+12x-8x=-24

Add like terms

12x-13x=-24

-x=-24

divide by 1

x=24

5 0
3 years ago
Some one has $200 and they want to share it with 4 freinds how much money does each person get
Musya8 [376]
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3 0
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Read 2 more answers
04. A school band charges a $160 flat fee plus $40 an hour to play.
Degger [83]

Answer:

Step-by-step explanation:

\frac{320-160}{40}=\frac{160}{40}=4

School band played for 4 hours.

3 0
3 years ago
Which autocad command can we use to quickly calculate the area and perimeter of a closed region defined by a polyline?
polet [3.4K]

The answer is: The Area command.

The explanation is shown below:

1. The Area command is a very useful command in AutoCad, and you can use it to calculate  the area and the perimeter of a closed region draw with a polyline.

2. To use this command, you only need to type AREA and press the enter button. Then, you must select the points of the closed region and press enter again. Once you do this, the software will show you the perimeter and the area.

4 0
3 years ago
Let A = {a, b, c}, B = {b, c, d}, and C = {b, c, e}. (a) Find A ∪ (B ∩ C), (A ∪ B) ∩ C, and (A ∪ B) ∩ (A ∪ C). (Enter your answe
wariber [46]

Answer:

(a)

A\ u\ (B\ n\ C) = \{a,b,c\}

(A\ u\ B)\ n\ C = \{b,c\}

(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}

(A\ u\ B)\ n\ C = (A\ u\ B)\ n\ (A\ u\ C)

(b)

A\ n\ (B\ u\ C) = \{b,c\}

(A\ n\ B)\ u\ C = \{b,c,e\}

(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}

A\ n\ (B\ u\ C) = (A\ n\ B)\ u\ (A\ n\ C)

(c)

(A - B) - C = \{a\}

A - (B - C) = \{a,b,c\}

<em>They are not equal</em>

<em></em>

Step-by-step explanation:

Given

A= \{a,b,c\}

B =\{b,c,d\}

C = \{b,c,e\}

Solving (a):

A\ u\ (B\ n\ C)

(A\ u\ B)\ n\ C

(A\ u\ B)\ n\ (A\ u\ C)

A\ u\ (B\ n\ C)

B n C means common elements between B and C;

So:

B\ n\ C = \{b,c,d\}\ n\ \{b,c,e\}

B\ n\ C = \{b,c\}

So:

A\ u\ (B\ n\ C) = \{a,b,c\}\ u\ \{b,c\}

u means union (without repetition)

So:

A\ u\ (B\ n\ C) = \{a,b,c\}

Using the illustrations of u and n, we have:

(A\ u\ B)\ n\ C

(A\ u\ B)\ n\ C = (\{a,b,c\}\ u\ \{b,c,d\})\ n\ C

Solve the bracket

(A\ u\ B)\ n\ C = (\{a,b,c,d\})\ n\ C

Substitute the value of set C

(A\ u\ B)\ n\ C = \{a,b,c,d\}\ n\ \{b,c,e\}

Apply intersection rule

(A\ u\ B)\ n\ C = \{b,c\}

(A\ u\ B)\ n\ (A\ u\ C)

In above:

A\ u\ B = \{a,b,c,d\}

Solving A u C, we have:

A\ u\ C = \{a,b,c\}\ u\ \{b,c,e\}

Apply union rule

A\ u\ C = \{b,c\}

So:

(A\ u\ B)\ n\ (A\ u\ C) = \{a,b,c,d\}\ n\ \{b,c\}

(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}

<u>The equal sets</u>

We have:

A\ u\ (B\ n\ C) = \{a,b,c\}

(A\ u\ B)\ n\ C = \{b,c\}

(A\ u\ B)\ n\ (A\ u\ C) = \{b,c\}

So, the equal sets are:

(A\ u\ B)\ n\ C and (A\ u\ B)\ n\ (A\ u\ C)

They both equal to \{b,c\}

So:

(A\ u\ B)\ n\ C = (A\ u\ B)\ n\ (A\ u\ C)

Solving (b):

A\ n\ (B\ u\ C)

(A\ n\ B)\ u\ C

(A\ n\ B)\ u\ (A\ n\ C)

So, we have:

A\ n\ (B\ u\ C) = \{a,b,c\}\ n\ (\{b,c,d\}\ u\ \{b,c,e\})

Solve the bracket

A\ n\ (B\ u\ C) = \{a,b,c\}\ n\ (\{b,c,d,e\})

Apply intersection rule

A\ n\ (B\ u\ C) = \{b,c\}

(A\ n\ B)\ u\ C = (\{a,b,c\}\ n\ \{b,c,d\})\ u\ \{b,c,e\}

Solve the bracket

(A\ n\ B)\ u\ C = \{b,c\}\ u\ \{b,c,e\}

Apply union rule

(A\ n\ B)\ u\ C = \{b,c,e\}

(A\ n\ B)\ u\ (A\ n\ C) = (\{a,b,c\}\ n\ \{b,c,d\})\ u\ (\{a,b,c\}\ n\ \{b,c,e\})

Solve each bracket

(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}\ u\ \{b,c\}

Apply union rule

(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}

<u>The equal set</u>

We have:

A\ n\ (B\ u\ C) = \{b,c\}

(A\ n\ B)\ u\ C = \{b,c,e\}

(A\ n\ B)\ u\ (A\ n\ C) = \{b,c\}

So, the equal sets are:

A\ n\ (B\ u\ C) and (A\ n\ B)\ u\ (A\ n\ C)

They both equal to \{b,c\}

So:

A\ n\ (B\ u\ C) = (A\ n\ B)\ u\ (A\ n\ C)

Solving (c):

(A - B) - C

A - (B - C)

This illustrates difference.

A - B returns the elements in A and not B

Using that illustration, we have:

(A - B) - C = (\{a,b,c\} - \{b,c,d\}) - \{b,c,e\}

Solve the bracket

(A - B) - C = \{a\} - \{b,c,e\}

(A - B) - C = \{a\}

Similarly:

A - (B - C) = \{a,b,c\} - (\{b,c,d\} - \{b,c,e\})

A - (B - C) = \{a,b,c\} - \{d\}

A - (B - C) = \{a,b,c\}

<em>They are not equal</em>

4 0
3 years ago
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