What is equivalent to the product of nine and b cubed

None is necessarily true.

Even though you have your money in an interest-bearing savings vehicle, its value (purchasing power) may actually decrease if the interest rate is not at least as great as the inflation rate.

In periods of inflation, the value of money decreases over time. In periods of deflation, the value of money increases over time. It tends to be difficult to regulate an economy so the value of money remains constant over time.

The present value of money is greater than the future value in inflationary times. The opposite is true in deflationary times.

_____
In the US in the middle of the last century, inflation rates were consistently 2-3% per year and savings interest rates were perhaps 4-6%. Money saved actually increased in value, and the present value of money was greater than the future value. These days, inflation is perhaps a little lower, but savings interest rates are a lot lower, so savings does not outpace inflation the way it did. The truth or falsity of all these statements depends on where and when you're talking about.

3 0

3 years ago

This year, 1,272 students enrolled in night courses a a local college. Last year only 1,200 students enrolled. What was the perc

Ahat [919]

The percent increase in enrollment is 6 %

The operation used in first step is finding the difference between final value and initial value

<h3><u>Solution:</u></h3>

Given that This year, 1,272 students enrolled in night courses a a local college

Last year only 1,200 students enrolled.

To find: percent increase in the enrollment

The percent increase between two values is the difference between a final value and an initial value, expressed as a percentage of the initial value.

<em><u>The percent increase is given as:</u></em>

$\text { percentage increase }=\frac{\text { final value - initial value}}{\text { initial value }} \times 100$

Here initial value (last year) = 1200 and final value(this year) = 1272

Substituting the values in above formula,

$\begin{aligned}&\text { percentage increase }=\frac{1272-1200}{1200} \times 100\\\\&\text { percentage increase }=\frac{72}{1200} \times 100=6\end{aligned}$

Thus percent increase is 6 %

4 0

3 years ago

Find the perimeter and area , Please help me on this will give brainlist

Ronch [10]

Answer:

Area: x^2+x-6

Perimeter: 4x+2

Step-by-step explanation:

Area: multiply x+3 and x-2 and combine the like terms

Perimeter: multiply the length and width by two, then combine the like terms.

7 0

3 years ago