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3 years ago

What is the classification of the number one

Mathematics

1 answer:

aivan3 [116]3 years ago

7 0

Answer:sry just tryna get points

Step-by-step explanation:jakakakkakakakakakakaka

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Talia has 2 red, 1 blue, and 4 green balls of the same size in a bag. Talia pulls one ball out of the bag without looking.

REY [17]

Answer:

2/7

Step-by-step explanation:

the probability is red/ total so 2/7

8 0

3 years ago

Read 2 more answers

519 divided by 6 and 915 divided by 7 and 439 divided by 7 and 812 divided by 9 which one does not have a two digit quotient.

Setler [38]

519/6=86.5

915/7=130.7142

439/7=62.7142

812/9=90.2222

so i think its the 1st on but i may be wrong.

5 0

3 years ago

timofeeve [1]

Answer:

what should we find here

Step-by-step explanation:

confused

conform

5 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2