If x is the hypotenuse then
hyp^2 = 4^2 + 5^2
hyp^2 = 41
hypotenuse =
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6.403124
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if x is a leg then
leg^2 = 5^2 - 4^2
leg^2 = 25 - 16
leg^2 = 9
leg =3
Answer:
The answer is -4
Step-by-step explanation:
-2x-6<=1
-2(-4)-6<=1
8-6<=1
2<=1 which is False
-2x-6<=1
-2(-3)-6<=1
6-6<=1
0<=1 which is True
-2x-6<=1
-2(-2)-6<=1
4-6<=1
-2<=1 which is True
-2x-6<=1
-2(-1)-6<=1
2-6<=1
-4<=1 which is True
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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<span>[3 - (4 + 32 * 8) ÷ 4]
=</span>[3 - (4 + 4) ÷ 4]
= 3 - 8 ÷ 4
= 3 - 2
= 1
5w^2 = A
You would multiply the width (w) by 5 because it's 5 times more than twice it's width. Then w (Width) would be to the power of 2 because it's 5 times more than twice its width. And this will all equal the Area (a)
