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2 years ago

The slope of the line whose equation is 3y + 2x = 1 is: A.)-2/3 B.)-3/2 C.)1/3

Mathematics

1 answer:

mojhsa [17]2 years ago

4 0

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 3y + 2x = 1 into this form

Subtract 2x from both sides

3y = - 2x + 1 ( divide all terms by 3 )

y = - $\frac{2}{3}$ x + $\frac{1}{3}$ ← in slope- intercept form

with slope m = - $\frac{2}{3}$ → A

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3 years ago

A rectangle has a perimeter of 52 cm and an area of 144 square cm. Find its length and width if they are in whole numbers.

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3 years ago

The coordinates of the midpoint of gh are m(-13/2,-6) and the coordinates of one endpoint are g(-4,1). what is the other endpoin

Alex777 [14]

Applying the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

<h3>How to Apply the Midpoint Formula?</h3>

The midpoint formula, which can be used in determining the coordinates of the midpoint between two endpoints is usually expressed as: M[(x1 + x2)/2, (y1 + y2)/2].

Given the following coordinates:

Midpoint of GH --> m(-13/2,-6) = (x, y)

One endpoint ---> G(-4, 1) = (x1, y1)

The other endpoint ---> (x2, y2)

Plug in the values into the formula used in calculating the midpoint:

m(-13/2,-6) = [(-4 + x2)/2, (1 + y2)/2]

Solve for x2

-13/2 = (-4 + x2)/2

-13/2 × 2 = -4 + x2

-13 = -4 + x2

-13 + 4 = x2

-9 = x2

x2 = -9

Solve for y2

-6 = (1 + y2)/2

2(-6) = 1 + y2

-12 = 1 + y2

-12 - 1 = y2

-13 = y2

y2 = -13

Thus, using the midpoint formula, the coordinates of the other endpoint are: (-9, -13).

Learn more about the midpoint formula on:

brainly.com/question/13115533

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1 year ago

4) Stan owns 4 5 of an acre of land. Of that, 2 3 of the land is fenced. How many acres of land is fenced? A

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2 years ago

Read 2 more answers

What is the vertex of the graph of y = −1(x − 2)2 + 3

Alona [7]

$Vertex: \ (2,3)$

<h2>Explanation:</h2>

The vertex form of the equation of a parabola is given by the following form:

$f(x)=a(x-h)^2+k \\ \\ Where: \\ \\ a:Leading \ Coefficient \\ \\ (h,k):Vertex \ of \ the \ parabola$

In this exercise, we have the following equation:

$y=-(x-2)^2+3$

From here, we can conclude that:

$Leading \ coefficient: \ -1 \\ \\ Vertex: \ (2,3)$

Since the leading coefficient is less than zero, the parabola open downward. So, the graph is shown below and the vertex has been indicated.

<h2>Learn more:</h2>

Finding leading coefficient: brainly.com/question/1469367

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3 years ago