Y=x^2
substitute the values into the original equation
0=4^2
0=16
No it does not satisfy the equation because 0 does not equal to 16
Your answer for 15 is D or C. For 16 I’m estimating 125?
Answer:
x=3 or x=−9
Step-by-step explanation:
Step 1: Subtract 27 from both sides.
x2+6x−27=27−27
x2+6x−27=0
Step 2: Factor left side of equation.
(x−3)(x+9)=0
Step 3: Set factors equal to 0.
x−3=0 or x+9=0
x=3 or x=−9
Answer:
x=3 or x=−9
Answer:
(2a, b )
Step-by-step explanation:
Given the endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is
[ 
(x₁ + x₂ ), (y₁ + y₂ ) ]
Here (x₁, y₁ ) = N(2a, 2b) and (x₂, y₂ ) = P(2a, 0), thus
midpoint = [ (2a + 2a), (2b + 0 ) ] = (2a, b )
Answer: i love brinly its the best
the value of x is 4, make m||n
Step-by-step explanation:
sorry if this is wrong
