Ask question

Ask question

All categories

nataly862011 [7]

3 years ago

13

Beau can process 36 envelopes for a mailing in 24 minutes. At this rate, how many minutes will it take to process 120 envelopes?

Please show how to solve it.

1 answer:

Crazy boy [7]3 years ago

4 0

This is a proportion problem

36/24 = 120/x

then do cross multiplication and you have x= 7.2

You might be interested in

BRAINLYIST AND 20 PTS!!! What is the surface area of this design? 360in 280in 76in 392in

guapka [62]

Answer:

392 I got that correct as well

3 0

2 years ago

Read 2 more answers

What is the side length, in inches, of the pets

tatiyna

Candy draws a square design with a side length of x inches for the window at the pet shop. She takes the design to the printer and asks for a sign that has an area of 16x2 – 40x + 25 square inches. What is the side length, in inches, of the pet shop sign?

Answer:

the length of the sign is $4x-5$ inches

Step-by-step explanation:

Given

Area of the square of design = $16x^{2} -40x+25$

First we find the roots of equation $16x^{2} -40x+25=0$

The roots of the quadratic equation $ax^{2} +bx^{2} +c=0$ are given by

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

where $a=16, b=-40, c=25$

$x=\frac{40\pm\sqrt{(-40)^2-4\times 16\times 25}}{2\times 16}$

$x=\frac{40\pm\sqrt{1600-1600}}{32}$

$x=\frac{40\pm\sqrt{0}}{32}$

$x=\frac{40}{32}$

$x=\frac{5}{4}$

$4x=5\\4x-5=0$

That is, the factors of the polynomial $16x^{2} -40x+25$ are $4x-5$ and $4x-5$ .

So, Area of the square design = $16x^{2} -40x+25$ = $(4x-5)^{2}$

Area of a square = Length^2

Thus, the length of the sign is $4x-5$ inches

7 0

3 years ago

The centers for disease control and prevention reported that 25% of baby boys 6-8 months old in the united states weigh more tha

melisa1 [442]

Answer:

0.1971 ( approx )

Step-by-step explanation:

Let X represents the event of weighing more than 20 pounds,

Since, the binomial distribution formula is,

$P(x)=^nC_r p^r q^{n-r}$

Where, $^nC_r=\frac{n!}{r!(n-r)!}$

Given,

The probability of weighing more than 20 pounds, p = 25% = 0.25,

⇒ The probability of not weighing more than 20 pounds, q = 1-p = 0.75

Total number of samples, n = 16,

Hence, the probability that fewer than 3 weigh more than 20 pounds,

$P(X$

$=^{16}C_0 (0.25)^0 (0.75)^{16-0}+^{16}C_1 (0.25)^1 (0.75)^{16-1}+^{16}C_2 (0.25)^2 (0.75)^{16-2}$

$=(0.75)^{16}+16(0.25)(0.75)^{15}+120(0.25)^2(0.75)^{14}$

$=0.1971110499$

$\approx 0.1971$

3 0

3 years ago

- 4/7 • (- 3/4) <br> Find the product simplify if possible

Reil [10]

Answer:

I believe the answer is 3/7. Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Given f(x)= 3x+21. A. F(4)=B. F(X)= 50, X=2. C. F(-5)=D. F(X)= -34, X=

nignag [31]

The given function is

$f(x)=3x+2$

A . f(4) means we have to evaluate the function when x = 4.

$f(4)=3(4)+2=12+2=14$ <h2>Therefore, f(4) = 14.</h2>

B. f(x) = 50 means we have to evaluate the function when y = 50.-

$\begin{gathered} 50=3x+2 \\ 50-2=3x \\ x=\frac{48}{3} \\ x=16 \end{gathered}$ <h2>Therefore, f(16) = 50.</h2>

C. f(-5) means we have to evaluate the function when x = -5.

$f(-5)=3(-5)+2=-15+2=-13$ <h2>Therefore, f(-5) = -13.</h2>

D. f(x) = -34.

$\begin{gathered} -34=3x+2 \\ -34-2=3x \\ x=\frac{-36}{3} \\ x=-12 \end{gathered}$ <h2>Therefore f(-12) = -34.</h2>

4 0

2 years ago