A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
I believe it is the ratio 3 : 1.
<u>18 students chose the turkey sandwich</u>.
Since the class has a total of 24 students, we can deduce that <u>6 students chose the vegetarian sandwich</u>.
This gives us a ratio of 18 : 6.
When simplified, we get a ratio of 3 : 1.
No because 4=4.00000 and there is that much more than 4.00000 so 4.002 is more
Answer:
3 x 34 = 102 + 2 = 104 is your answer just do the equation
Answer:
h(-4) = -4
Step-by-step explanation:
Since x is given (x = -4). Then, all you need to do is log in -4 for each value of x
h(-4) =
−
(
−
4
)
2
-3(-4)
h(-4) = -(16) + 12 = -4
