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Nat2105 [25]
3 years ago
8

Interruption attacks are also called ___ attacks:

Computers and Technology
1 answer:
Lelu [443]3 years ago
4 0

Answer:

Interruption attack are also referred to as Denial Of Service(DOS) attack.

Explanation:

Interruption attack are also called denial of service.The main aim of  interruption attack or Denial Of Srvice attack is to make resources unavailable.

For example:- wordpress.com had an DOS attack that took down their servers hence the service was unavailable for it's users.

Hence we conclude that the answer to this question is Denail of Service (DOS).

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Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ at brainly.com/question/19705654

#SPJ1

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URGENTT 2 SIMPLE EASY QUESTIONS PLZZ HELP ION UNDERSTAND COMPUTERR ILL GIVE U BRAINLEST
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Answer:

I'll happy to help

Explanation:

Please make your clear. I couldn't understand!

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