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nadezda [96]
4 years ago
14

Simplify 6x+1 ty try to answer this and explain

Mathematics
1 answer:
Sergeu [11.5K]4 years ago
7 0

Simplify the Value of:

6x     +       1   The equation is already simplified, There are no like terms.

You cannot factor    6x     +   1       either




Domain of:

6x     +    1

Solution:      [  - ∞    <    x    <   ∞ ]

Interval Notation:   [ (- ∞,  ∞) ]


Range of:

6x      +    1

Solution:    [    - ∞    <    f(x)   <    ∞ ]

Interval Notation:   [   (- ∞, ∞) ]


Parity of:

6x     +    1   =====>    Neither  even  nor odd


Axis interception points of:

6x   +   1

x-   Intercepts  ( - 1 / 6,   0 )

y-  Intercepts    ( 0,   1 )


Inverse of:

6x    +   1  =====>    x   -    1 / 6

Slope of:

6x    +   1

Answer:    ======>    m      =         6




Hope that helps!!!!!!!!!!                                        : )


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The area of the required triangle is <u>9/π²(3  + √3)</u> sq. units.

In the question, we are given that a triangle is inscribed in a circle. The vertices of the triangle divide the circle into three arcs of lengths 3, 4, and 5.

We are asked for the area of the triangle.

Now, the circumference of the circle = 3 + 4 + 5 = 12 units.

The formula for the circumference is 2πr, which gives is:

2πr = 12,

or, r = 6/π.

The length of the arcs are proportional to its central angle, making the angles: 3θ, 4θ, and 5θ, which needs to sum up to 360°, giving us θ = 360°/12 = 30°.

Thus, the three arcs subtends angles of θ₁ = 3θ = 90°,θ₂ = 4θ = 120°, and θ₃ = 5θ = 150°.

The area of the circle can be calculated as:

Area = (1/2)r² sin θ₁ + (1/2)r² sin θ₂ + (1/2)r² sin θ₃ = r²/2(sin θ₁ + sin θ₂ + sin θ₃).

Substituting the values, we get:

Area = 36/2π²(sin 90° + sin 120° + sin 150°),

or, Area = 36/2π²( 1 + √3/2 + 1/2),

or, Area = 9/π²(3  + √3).

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Answer:

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Step-by-step explanation:

Let t be the time taken for each train

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So we add the distance of both trains and set it equal to 294

95t + 115t = 294

210 t =294

t = 1.4

So, it will take 1.4 hours for the two trains to be 294 miles apart

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