Answer:
The slope of a line that includes the points (4, -2) and (5, 0) is 2
Step-by-step explanation:
You know that the formula y - y1 = m(x - x1) is the point-slope form of the equation of a line where m is the slope of a line.
The line must include the points (4, -2) and (5, 0). So, being:
- (x,y)= (4,-2)
- (x1,y1)= (5, 0)
and replacing in the point-slope form of the equation of a line:
-2-0=m(4-5)
You solve the equation for m and get:
-2=m*(-1)
m=2
<u><em>The slope of a line that includes the points (4, -2) and (5, 0) is 2</em></u>
Answer:
Step-by-step explanation:
what is she considering? I would need more information to complete the probolem
Answer:
29) discriminant is positive
30) discriminant is 0
31) discriminant is negative
Step-by-step explanation:
the graph of a quadratic function y=ax^2 + bx + c is shown. Tell whether the discriminant of ax^2 + bx + c = 0 is positive, negative, or zero.
In the graph of question number 29 we can see that the graph intersects the x axis at two points
so the equation has 2 solutions.
When the equation has two solution then the discriminant is positive
In the graph of question number 30 we can see that the graph intersects the x axis at only one point
so the equation has only 1 solution.
When the equation has only one solution then the discriminant is equal to 0
In the graph of question number 30 we can see that the graph does not intersects the x axis
so the equation has 2 imaginary solutions.
When the equation has two imaginary solutions then the discriminant is negative
361 + 173 =361+173
(a+b)+(a-b)=361+173
a+b=a-b=534
2a=534
a=267
267+b=361
b=94
the two numbers are 267 and 94
