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2 years ago

13

What is a counter example for, when it rains, it pours?

2 answers:

lianna [129]2 years ago

8 0

A counterexample is a statement that simply disproves another statement.

You could disprove "when it rains, it pours" by saying "sometimes when it rains, the rain is light."

Eva8 [605]2 years ago

7 0

A statement that disaproves another statement

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One page of a petition can hold p signatures. You were able to get 4p+5 people to sign the petition. Your friend was able to get

leva [86]

Answer:

6p - 2

Step-by-step explanation:

The expression that needs to be made in this question refers to the total number of people that signed the petition. To calculate this we need to add the total number of signatures that both you and your friend were able to acquire. Once we do this we simply combine like terms in order to simplify the expression as much as possible.

4p + 5 + 2p - 3

4p + 2p + 5 - 3

6p - 2

Therefore, the total and simplified expression for the total number of signatures would be 6p - 2

8 0

2 years ago

Solve x3 = 64 over 27.

const2013 [10]

x^3 = 64/27

x^3 = (4*4*4)/(3*3*3)

x^3 = (4/3)^3

x = 4/3

ans is d

5 0

2 years ago

Read 2 more answers

4/5 divided by 1/3 plus 1/5 minus 3/5

r-ruslan [8.4K]

Answer:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

Step-by-step explanation:

Considering the expression

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

Solution Steps:

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}$

as

$\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}$

so

$=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}$

$=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}$

join $\frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}$

so

$=\frac{4}{5\left(-\frac{1}{15}\right)}$

$\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a$

$=\frac{4}{-5\cdot \frac{1}{15}}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}$

$=-\frac{4}{5\cdot \frac{1}{15}}$

$\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}$

so

$=-\frac{4}{\frac{1}{3}}$

$\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}$

so

$=-\frac{12}{1}$

$\mathrm{Apply\:rule}\:\frac{a}{1}=a$

$=-12$

Therefore

$\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12$

4 0

2 years ago

To see how costly it would be for other people to compete a similar cycling tour, you decide to work out two averages and compar

Damm [24]

Group A

Money spent by Person 1 = £500

Money spent by Person 2 = £600

Money spent by Person 3 = £900

Money spent by Person 4 = £450

Sum of money spent by group A = £2,450

Average money spent by group A = $\frac{2,450}{4}$

⇒ Average money spent by group A = £612.5

Group B

Money spent by Person 1 = £700

Money spent by Person 2 = £500

Money spent by Person 3 = £680

Money spent by Person 4 = £500

Sum of money spent by group B = £2,380

Average money spent by group B = $\frac{2,380}{4}$

⇒ Average money spent by group B = £595

Hence, Group B had lower average spend.

4 0

2 years ago

Let U = {5, 10, 15, 20, 25, 30, 35, 40)

Katen [24]

Answer:

auc=5,10,15,20,30,40

5 0

2 years ago