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nataly862011 [7]
3 years ago
6

Please solve the following : 2.25x + 15 = 9.5x + 0.5

Mathematics
2 answers:
Natalka [10]3 years ago
8 0

Answer:

x=2

Step-by-step explanation:

2.25x-9.5x=.5-15

-7.25x=-14.5

x=2

vazorg [7]3 years ago
7 0
  • <em>Answer:</em>

<em>x = 2</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there !</em>

<em>2.25x + 15 = 9.5x + 0.5</em>

<em>15 - 0.5 = 9.5x - 2.25x</em>

<em>14.5 = 7.25x</em>

<em>x = 14.50/7.25</em>

<em>x = 2</em>

<em>Good luck !</em>

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Which expression is equal to (−4x2−1)(2x2+3)?
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a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

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b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
3 years ago
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