Answer:
Radius:3.14
Circumference: 6.28
Step-by-step explanation:
C=2(pi)(r)
replace r with 1
and you get 6.28
R=(pi)(r)^2
Replace r with 1
multiply and you get 3.14
Answer:
13/1700
Step-by-step explanation:
so you do 13/17 x 1/100 which is 13/1700 please mark brainliest
Answer:If you would like to know what will the approximate population be after 3 years, you can calculate this using the following steps:
an initial population ... 298 quail
an annual rate ... 8%
an exponential function to model the quail population:
f = 298(1+8%)^t = 298(1+8/100)^t
f ... quail population
t ... time (years)
t = 3 years
f = 298(1+8/100)^t = 298(1.08)^3 = 375.4 quail
375.4 quail after 3 years.
He would have four fields. Since the area of 1/2 milex1/2 mile is 1/4, and 1x1 is 1, so 4 fields make up the land.
Answer:
373.8mmHg
Step-by-step explanation:
a =height (in km) above sea level,
the pressure P(a) (in mmHg) is approximated given as
P(a) = 760e–0.13a .
To determine the atmospheric pressure at 5.458 km, then we will input into the equation
P(5.458km) = 760e–0.13a .
= 760e^(-0.13×5.458)
=760e^-(0.70954)
= 760×0.4919
=373.8mmHg
Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg
