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3 years ago

10

Kevin makes several cone-shaped candles. He uses a cone mold that has a height of 15 centimeters and a diameter of 10 centimeter

s. How much wax is needed to make 3 cone-shaped candles?

1 answer:

Natalka [10]3 years ago

8 0

Answer:

1,177.5cm^3 of candle wax will be required.

Step-by-step explanation:

The attached files contain further information so please check them.

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$m\angle ABC = 51°$

Step-by-step explanation:

11. By inscribed angle theorem:

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12. Again by inscribed angle theorem:

$(5x+11)°=\frac{1}{2} \times (16x-26)°\\\\2\times (5x+11)°= (16x-26)°\\(10x+22)°= (16x-26)°\\10x + 22 = 16x - 26\\22+26 = 16x - 10x\\48= 6x\\\\x = \frac{48}{6}\\\\\huge \purple{\boxed {x = 8}}\\m\angle ABC = (5x+11)°\\m\angle ABC = (5\times 8+11)°\\m\angle ABC = (40+11)°\\\huge \orange{\boxed {m\angle ABC = 51°}} \\$

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Step-by-step explanation:

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Answer:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

Step-by-step explanation:

Given

$S = \{V,W,X,Y,Z\}$

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Required

The probability model

To do this, we simply calculate the probability of each container.

So, we have:

$P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20$

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$P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20$

$P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20$

$P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20$

So, the probability model is:

$\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}$

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