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3 years ago

Please help thank you

Mathematics

1 answer:

worty [1.4K]3 years ago

7 0

Answer:

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“. The sides of this triangle have been named as Perpendicular, Base and Hypotenuse. Here, the hypotenuse is the longest side, as it is opposite to the angle 90°.

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Petra jogs 5 miles in 40 minutes at the rate how long would it take her to jog 11 miles

KatRina [158]

88 minutes (1 hour and 28 mins)

Since 5 miles takes 40 minutes, multiplying both numbers by 2 gets you to 10 miles in 80 minutes. To get the extra 1 more miles you have to find the unit rate

5 miles in 40 minutes : divided both numbers by 5 to get
1 mile in 8 minutes
add the one mile in 8 minutes to the 10 miles in 80 mins and you get 11 miles in 88 minutes

6 0

3 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

Let $\bar X$ = sample average salary

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

3 years ago

7x what gives me 1 can someone answer I'm new

Lelu [443]

Doing (7x÷7) I think equals 1

3 0

3 years ago

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paige spent $7.55 on some report covers and one lanyard at the spirit shop. Each report cover costs $0.35 and the layard cost $6

fomenos

Answer:

The answer is 3.

Step-by-step explanation:

7.55-6.50=1.05

1.05/.35=3

8 0

3 years ago

Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),

butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks, Height

0, 3

1, 4.8

2, 6.6

3, 8.4

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant A per week is therefore;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week$

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks, Height

2, 7.3

3, 8.7

4, 10.1

The rate of change of height, H per week, t, $\left (\dfrac{dH}{dt} \right )$ for plant B per week is given as follows;

$\dfrac{dH}{dt} = \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week$

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0

3 years ago

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