Question

Fill in each box with the probability of the event that it represents. The following questions can be answered using your area model.
pleeeeaaseee help!!!!

Answer 1

Answer:

$a. \ \dfrac{1}{36}$

$b. \ \dfrac{4}{9}$

$c. \ \dfrac{5}{6}$

Step-by-step explanation:

The given probabilities are; P(Orange) = 1/3, P(Blue) = 1/6, P(Purple) = 1/2

The probability of rolling any of the six numbers of the six-sided die = 1/6

a. The probability of simultaneously 'rolling a 3' and 'spinning blue', P(3 and Blue) is given as follows;

P(rolling a 3) = 1/6, P(Blue) = 1/6

∴ P(3 and Blue) = (1/6) × (1/6) = 1/36

P(3 and Blue) = 1/36

$P(3 \ and \ Blue) = \dfrac{1}{36}$

b. The probability of either 'rolling a 1' or 'spinning Orange', P(1 or Orange), is given as follows;

P(rolling a 1) = 1/6, P(Orange) = 1/3

P(1 or Orange) = P(rolling a 1) + P(Orange) - P(1 and Orange)

Where;

P(1 and Orange) = (1/6) × (1/3) = 1/18

∴ P(1 or Orange) = 1/6 + 1/3 - 1/18 = 4/9

P(1 or Orange) = 4/9

$P(1 \ or \ Orange) = \dfrac{4}{9}$

c. The probability of not spinning a blue, P(not Blue) is given as follows;

P(not Blue) = P(rolling all outcomes of the die) and (The sum of the spin probabilities - P(Blue)

∴ P(not Blue) = 1 × ((1/3 + 1/6 + 1/2) - 1/6) = 1 × (1 - 1/6) = 5/6

P(not Blue) = 5/6

$P(not \ Blue) = \dfrac{5}{6}$