You just need to try with all of the pair f.ex
0,-2 -> put 0 in the x-> y=8*0-2=-2 so ok it is q possible pair of the function..
You try every pair till you find set where all the pairs fit
So set 1
1 and 6: 8*1-2=6 ok
2 and 14 : 8*2-2=14 ok
Hope I could help
Answer:
Step-by-step explanation:
H
Since someone answered wrongly I'll try to give the correct answer without the given xs. It won't matter. We're looking for a set of points which satisfy
y = f(x) = x² + 3
A. f(7)=7² + 3 = 52, not -2, so not A.
B. f(-2)=(-2)² + 3 = 7, not 1, so not B
C. f(-2)=7, that's good so far.
f(-2)=(-1)²+3=1+3=4, good
f(0) = 0²+3 = 3, good
f(1)=1²+3 = 4, good
f(2) = 2²+3 = 7, good
Answer: C
We'll rule out D. f(1)=1²+3=4, not -2, so not D.
