643=4x160+n write what n represents in the division problem

An airplane needs to reach a velocity of 203.0 km/h to take off. On a 2000 m runway, what is the minimum acceleration necessary

Aliun [14]

Answer:

1.59 m/s²

Step-by-step explanation:

Acceleration = change in Velocity over time. Mathematically it is represented as Δv/Δt

Given values in the question:

Final velocity 203.0 km/h which is equal to (203/3.6)m/s = 56.39 m/s
distance 2000 m
Initial velocity is 0 m/s

To use the equation for acceleration time is needed.

velocity= distance/time

(203/3.6) = 2000/time mltiplying both sides by time

(203/3.6) x time = 2000 making time subject of the formula

time = 2000/(203/3.6)

time = 35.47 seconds

Substituting into the acceleration equation

acceleration =Δv/Δt

=(56.39- 0)/35.47

= 56.39/35.47

=1.59 m/s²

6 0

3 years ago

Which expression represents the volume of the pyramid? One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3 One-th

anyanavicka [17]

Answer:

1/3(5.2)h cm³

Step-by-step explanation:

A solid right pyramid has a regular hexagonal base with an area of 5.2 cm2 and a height of h cm. Which expression represents the volume of the pyramid?

One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3

One-third(5.2)h cm3 StartFraction 1 Over 3 h EndFraction(5.2)h cm3

Volume of the pyramid = 1/3 × area × height

Area = 5.2 cm²

Height = h cm

Volume of the pyramid = 1/3 × 5.2 cm² × h cm

= 1/3(5.2)h cm³

7 0

2 years ago

Read 2 more answers

A policyholder has probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims. C

Sladkaya [172]

Answer:

0.89.

Step-by-step explanation:

So, we are given the following data or parameters or information which is going to aid in the solution to this question or problem. So, the data or parameters are;

(1). "probability 0.7 of having no claims, 0.2 of having exactly one claim, and 0.1 of having exactly two claims."

(2). " distributed on the interval [0,60] and are independent."

(3). "The insurer covers 100% of each claim."

So, taking (1) above we will have;

(Total probability= 0.7 + 0.2 + 0.1 = 0.1)

A = { (0.7 × 0)^2 + (0.2 × 1)^2 + ( 0.1 × 2)^2 =( 0.4) +( 0.4) = 0.8.

0.8 + total probability = 0.8 + 0.1 = 0.9.

So, from the question, we are to "Calculate the probability that the total beneﬁt paid to the policyholder is 48 or less."

Hence, P< 48/A = P < 48/0.9 = P < 53.33.

Thus, 53.33/60 = 0.89.

6 0

3 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

Second box plot represents class second. From the second box plot, we get

$\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0

3 years ago

Whats the domain and range

Lerok [7]

Answer:

d= all the x values

r=all the y values

Step-by-step explanation:

7 0

3 years ago